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maths help

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That's simple as well.

First let me explain the differentiation of this function.

There are two ways to differentiate this:

Firstly you can bring the denominator on the upper side and change it's power to a negative like this:

12[(2x+1)^-2]

Then you can solve it by the method I told you in your other thread.

OR

You can use the product formula to solve it like this:

u/u = {v(du/dx) - u(dv/dx)} DIVIDED BY v^2

------------

Now integration is the anti-derivative or sum of a derivative. So for this question you should bring the denominator on the upper side and change it's power to a negative like this:

12[(2x+1)^-2

Now you can use the formula:

Integral [ (cx^n) dx ] = c { Integral [ (x^n) dx ] }

Meaning you should take 12 as a constant and keep it outside the integral, then integrate (2x+1)^-2.

Show me your attempt and I will help you further!

I hope that helps you!

Don't forget to press the Thanks Button!
 
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thats simple.if equation is in the form (ax+b)^n then use this formula for differentiation an(ax+b)^n-1.this is relatively a easy formula 4 such format.But remember do not forget to multiply the constant and this formula is only applicable 4 the given format.
 
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