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Maths M1....

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Had to do some thinking and here goes nothing

7(i)- F= Meu x R

R= weight of both boxes = 450 x 10 = 4500 N

Since the maximum value of P for the boxes to remain staitonary is 3150

3150 = Meu x 4500

Meu = 0.7


(ii) The max frictional force between box a and b = f= meu x R

f= 0.2 x 4500
f= 900 N
the max accelaration for the boxes to not slip over each other = f =ma
900 = 450a
a=2

(iii) The max possible value of P = Total friction = 3150 + 900 = 4050 N


Best of luck for exams :D
 
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