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maths P4 questions
- Thread starter utsav156
- Start date
utsav156 said:
You'll have 2 do a little hardwork if u want an answer to ur query,
U need help...ok
be polite in ur lang....otherwise....stop expectng that others will help u....
atleast the good one's wouldn't
My past experience on XPF says that...that was only to help u....
part ii)
we can use
work done by driving force=(gain or loss in pe and ke)+work done by frictional force
we know that work done by driving force is zero since he is free wheeling
find the loss in ke which will be 2240
so
0=-2240+wd against resistance
we also know the that the friction is the same as the AB part so to find the friction u must use ur ans from part i/250 since work done =force *distance
so that will leave u with 2240=friction(which i just told u how to find it out above)*d
find d
we can use
work done by driving force=(gain or loss in pe and ke)+work done by frictional force
we know that work done by driving force is zero since he is free wheeling
find the loss in ke which will be 2240
so
0=-2240+wd against resistance
we also know the that the friction is the same as the AB part so to find the friction u must use ur ans from part i/250 since work done =force *distance
so that will leave u with 2240=friction(which i just told u how to find it out above)*d
find d