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you had to add the triangle area too using the sin wala area wala formula :l it was area of the segment, not the major arc! And anwyay, it carried 4 marks(300/360)pi(15)^2
15 was the radius ryt?
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you had to add the triangle area too using the sin wala area wala formula :l it was area of the segment, not the major arc! And anwyay, it carried 4 marks(300/360)pi(15)^2
15 was the radius ryt?
686 i think.wat was da area f da major segment ....!!
yeah you had toi also added da area f da major segment n da triangle
no xD but i think so.r u cnfrm
yeah i got that too what was the answer to the last vector part?the triangle was equilateral so i used the 1/2*b*h .
got 686.5
the one below that?2 ratio 3
the triangle was equilateral so i used the 1/2*b*h .
got 686.5
In Q8 area of segment were we supposed to take pie as 3?
I didn't do it, how many marks will I loose?
I dont think the question asked us to take pie as 3!!In Q8 area of segment were we supposed to take pie as 3?
I didn't do it, how many marks will I loose?
im pretty sure question 8 didnt ask us to take pie as 3!!
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