Maths Paper 22 Tomorrow, Help Needed !!!!

[Ahsen420]

I have maths paper tomorrow so could anybody help me out with these questions from Past Papers so that I could revise better. I finished everything else on these papers. Just some questions left. I tried to understand by the Mark Scheme but it didn't help. I would be really thankful. THANK U, 14 questions

P2, ON 2007 : http://www.xtremepapers.me/CIE/Cambridg ... 7_qp_2.pdf
Q12, What do they mean by simplest form
Q15, Too much complicated

P21, MJ 2008 : http://www.xtremepapers.me/CIE/Cambridg ... 8_qp_2.pdf
Q19(b)
Q21

P21, ON 2008 : http://www.xtremepapers.me/CIE/Cambridg ... 8_qp_2.pdf
Q9, In equation of line,y=mx+c, what is meant by C
Q17(b)

P21, MJ 2009 : http://www.xtremepapers.me/CIE/Cambridg ... 9_qp_2.pdf
Q16, Which bisector do they mean
Q22(a)(c)(d)

P21, ON 2009 : http://www.xtremepapers.me/CIE/Cambridg ... _qp_21.pdf
Q4, Simplest way of doing this
Q18

P22, MJ 2010 : http://www.xtremepapers.me/CIE/Cambridg ... _qp_22.pdf
Q8, Little explaination needed
Q11(b)
Q15(c)ii

P21, ON 2010 : http://www.xtremepapers.me/CIE/Cambridg ... _qp_21.pdf
Q21(c)

 

[Smile27]

P2, ON 2007 : http://www.xtremepapers.me/CIE/Cambridg ... 7_qp_2.pdf
Q12, What do they mean by simplest form

Like in simplification of fractions 5/10 = 1/2, they're giving you set notation, from which you have to find a simpler term.

(a)

So, A intersecting A^1 .
Let's analyse it..? A^1 is everything BUT A. Intersection means find the common things between the two. So, what's common between the Set A and everything BUT A...? Nothing.

So, in simplest form, it would be expressed as "Phi".

(b)

A union A^1. This is similar to the one above, both sets are the same but the SIGNS are different.
Though intersection looks for common terms between sets, union doesn't; it's much stronger and not specific, hence combines/grasps etc. all the terms that are considered.

So, everything but A AND (union) A, means everything.
If you draw a circle A in the middle of the rectangle, and call the rectangle the universal set, when you shade A Prime, it would be the rectangular area not occupied by the Circle A. Then, when you shade A, that would be the circle. Think of the sign "union" as AND. When you add them both together, you get the universal set (which is expressing this in the simplest form).

(c)

Here, there are two operations; do the brackets first.
You can even draw the two sets in order to visualise it properly.

(A intersecting B) --> This is the small intersection between the two sets.

(A intersecting B^1) --> That is, A intersecting everything BUT B.
Think...What do A and B^1 have in common..? The set A, excluding the intersection part.

Now,

(The intersection of A and B) Union (A, excluding the intersection part)
Union is stronger, it adds both of them together. So, you get the complete set A.

And that's that for that question

Sets are kind of difficult to interpret sometimes and hard to handle. Just break the info. down into digestible pieces and use logic

Any questions, please ask.

 

[Smile27]

P2, ON 2007 : http://www.xtremepapers.me/CIE/Cambridg ... 7_qp_2.pdf

Q15, Too much complicated

Vectors. Not very complicated if you break it down

(a) Point C. 1/3a + 2/3b

OA = a; what's 1/3 of OA...?
The line is divided into six "sections" .. Find a third of that = 2.

OB = b; what's 2/3 of OB...?
The line is also divided into six "sections" .. Find two thirds of that = 4.

So now, you go up 2 sections (that's 1/3 a or line OA) and then you move left 4 sections (that's 2/3 b or line OB) And mark the point.

Hope its clear

Notice it says "position vector", that's the point's position according to "O".

(b)

Position vector of E in terms of a and b... That's the vector OE.

E in terms of a .. 1/2 a. Why? Because going from O to E, you have to travel 3 sections up on the line OA. this is 3/6 of a which is 1/2 of a.

Now, in terms of b.

From O to E, you have to travel two section to the right on the line OB. This is 2/6 of b which is 1/3 of b.

Put them together ... OE = 1/2a + 1/3b
("+" in this case because it's going in the direction of the vectors)

(c)

EB. You have to go from E to B.
We have to go parallel to line AO, that's -OA, so, we're travelling -a.
We have to go 3 sections down, that's 3/6 = 1/2.
That's -1/2a.

Now we travel across to B, on line OB, that's vector b. We have to cross 4 sections in order to reach b. That's 4/6 = 2/3b.

Put it together.. EB = -1/2a + 2/3b

I hope you understand

 

[Smile27]

P21, MJ 2008 : http://www.xtremepapers.me/CIE/Cambridg ... 8_qp_2.pdf
Q19(b)

19 (b)

To find the matrix...

[Matrix] multiplied by [Object A] = [Image B]

You have one unknown (the matrix), you have two knows (the points of the object and image). Plot them into an equation and solve. Remember to put the corresponding points, of the object and image, in the right positions.

[w x] * [2 3 2] = [-1 -1 -3]
[y z] [1 1 3] [ 2 3 2 ]

2w + x = -1
3w + x = -1
2w + 3x = -3

2y + z = 2
3y + z = 3
2y + 3z = 2

You can solve them as simultaneous equations.
In the end, you should get..

[0 -1]
[1 0]

It would help if you knew transformation matrices for reflection, rotation, enlargement, shear, stretch etc. But its always good to double-check this way.

 

[Smile27]

P21, ON 2008 : http://www.xtremepapers.me/CIE/Cambridg ... 8_qp_2.pdf
Q9, In equation of line,y=mx+c, what is meant by C
Q17(b)

In general, y= mx + c, "c" is where the line crosses the y-axis.
In this case, they have marked a point "C" and want you to find the co-ordinates... The Point "C" in this case is where the line crosses the x-axis.

I hope you can get the answer now...?
If not, you can ask.

17(b)

"p" is equal to one square. It's numerical value is given 2.
AB is parallel to p and is 4 squares. So, it's 4p = magnitude = 4 * 2 = 8.

 

[Smile27]

I'm sorry, I can't do anymore, my hands are tired of typing

I hope I helped you though... And hopefully, someone else out there will help you with your other questions.

But, anyways, good luck to you

 

[Ahsen420]

Thx for your hardwork, Smile27, and no need to do the rest of the questions. Cuz I got it from another Site.

 

[Smile27]

Your welcome

Ok, that's good