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Maths paper 3 (MAY june 10 paper 31)URGENT!!
- Thread starter diwash
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The answer can be easily obtained if you use the Pythagorean Principle. 
Here, try to find the right-angled triangle: the origin, the tangent point, and the centre of the circle - these three points form a 90-degree triangle due to the tangent.
Then, the origin to the circle centre (noted as |C.C|) is 2 * sqrt 2 , and the radius of the circle = 1. So (|z|)^2 should be (|C.C|)^2 - radius^2 = 8 - 1 = 7. So |z| = sqrt 7.
Here, try to find the right-angled triangle: the origin, the tangent point, and the centre of the circle - these three points form a 90-degree triangle due to the tangent.
Then, the origin to the circle centre (noted as |C.C|) is 2 * sqrt 2 , and the radius of the circle = 1. So (|z|)^2 should be (|C.C|)^2 - radius^2 = 8 - 1 = 7. So |z| = sqrt 7.