Maths Paper 4.. " How On Earth" DOUBTS QUESTIONS!

[The Chill Master]

can anyone solve 0580/41/m/j/10 question 8 last part

 

[ahmadumar]

Please solve these..

bro im away from.home for few days so dont have access to laptop. i hope some1 answers ur questions. but in case nobody does dnt worry just keep compiling i'll try when i get back

 

[dubi2pro]

bro im away from.home for few days so dont have access to laptop. i hope some1 answers ur questions. but in case nobody does dnt worry just keep compiling i'll try when i get back

thanks for replying BRO! no worries! i swear when i saw ahmadumar quoted your post. i was like thank god!

no worries. still have some days for paper!

 

[ahmadumar]

thanks for replying BRO! no worries! i swear when i saw ahmadumar quoted your post. i was like thank god!

no worries. still have some days for paper!

heheheh awwwww bro :'))
i am really really sorry for not being able to reply u now. please forgive me.
do alot pprs and mark them urself and write the total and then go over the wrong ones. and also if u know u r weak on any topic, open that topic in the book and do questions from there

 

[Student_Learner]

Pleaaaaaaaase help me with this stuff someone!
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w13_qp_41.pdf
Call me dumb but I've been stuck on it for ever!
Both the questions are from this paper itself..
Questions : 4 d
10 v
I'd be really grateful!

 

[Hello090078601]

Need help ASAP!

I'm stuck on this question, from O580/43/O/N/13 (October November 2013, 43, IGCSE)

It's Question 9ci and 9cii

c) The total number of lines in the first n diagram is 1/2n^3 + pn^2 + qn

i) When n=1, show that p+q=8.5

ii) By choosing another value of n and using the equation in part (c)(i), find the values of p and q.


Link to the paper: http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w13_qp_43.pdf

 

[FlameBlazer69]

Need help ASAP!

I'm stuck on this question, from O580/43/O/N/13 (October November 2013, 43, IGCSE)

It's Question 9ci and 9cii

c) The total number of lines in the first n diagram is 1/2n^3 + pn^2 + qn

i) When n=1, show that p+q=8.5

ii) By choosing another value of n and using the equation in part (c)(i), find the values of p and q.


Link to the paper: http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w13_qp_43.pdf

c) i) it says when n=1, show that p+q=8.5
so do 1/2n^3 + pn^2 + qn = 9 (number of lines of first diagram is 9)
substitute "1" in place of "n"
you get 1/2 + p + q = 9
so 1/2 + 8.5 = 9 :3

 

[Ayeshah.ahmed]

Please solve these..

i can help you with the first qjestion i.e water and lemonade question
make a simultaneous question out of it and solve it get w and l. the value you get for w is the final answer
therefore
2w+3L=36 (w for water and L for lemonade)
L-w=0.25
these are the two eqjations you have i hope you can solve them out simultanously

the for follwing quest it tells us y+Y=1
so again you need to equat it like this
from the small triangle imagine you wanted to make y the subject how would it be like
it would be 5/x
and like wise from the big triangle make Y the subject which would be 6/(x+2)
the make the final equation according to "y+Y=1"
which would be:
5/x+6/(x+2)=1
5x+10+6x/(x^2+2)=(1)
i hope you are able to solve it until its max and end up until the requirement
i couldve helped you with the other two papers but im unable to open them for some reason
for the last two questions (x^2-9x-10) the answer is (x-10)(x+1) get it by factorising the expression and for the perimeter find the answer of the equation (x^2+9x-10=0) where you will get x=-1 or x=10 take the postive value sincea legnth cant be negative substitute into the x and get the perimeter
hope i helped

 

[dubi2pro]

i can help you with the first qjestion i.e water and lemonade question
make a simultaneous question out of it and solve it get w and l. the value you get for w is the final answer
therefore
2w+3L=36 (w for water and L for lemonade)
L-w=0.25
these are the two eqjations you have i hope you can solve them out simultanously

the for follwing quest it tells us y+Y=1
so again you need to equat it like this
from the small triangle imagine you wanted to make y the subject how would it be like
it would be 5/x
and like wise from the big triangle make Y the subject which would be 6/(x+2)
the make the final equation according to "y+Y=1"
which would be:
5/x+6/(x+2)=1
5x+10+6x/(x^2+2)=(1)
i hope you are able to solve it until its max and end up until the requirement
i couldve helped you with the other two papers but im unable to open them for some reason
for the last two questions (x^2-9x-10) the answer is (x-10)(x+1) get it by factorising the expression and for the perimeter find the answer of the equation (x^2+9x-10=0) where you will get x=-1 or x=10 take the postive value sincea legnth cant be negative substitute into the x and get the perimeter
hope i helped

Yes You really helped! thaanks alot!

 

[Kshitij_2511]

Pleaaaaaaaase help me with this stuff someone!
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w13_qp_41.pdf
Call me dumb but I've been stuck on it for ever!
All the questions are from this paper itself..
Questions : 4 d
10 v
I'd be really grateful!

4d: connect a line from A to BD and obtain a right angled triangle.
next, use the sine rule. i.e. sine 40= (shortest distance/55)
therefore, shortest distance is 55 * sine 40
which is 33.35

 

[Student_Learner]

4d: connect a line from A to BD and obtain a right angled triangle.
next, use the sine rule. i.e. sine 40= (shortest distance/55)
therefore, shortest distance is 55 * sine 40
which is 33.35

But how can we be so sure that the line is the shortest distance and that we're forming a right angled triangle?

 

[Kshitij_2511]

But how can we be so sure that the line is the shortest distance and that we're forming a right angled triangle?

you must connect a straight line from A to BD and it will form a right angle triangle as you're splitting the triangle ABD into two, which i guess is an isosceles? and i assure you that it is the only way of finding the shortest distance; connect it on the diagram for easier use.

 

[Student_Learner]

you must connect a straight line from A to BD and it will form a right angle triangle as you're splitting the triangle ABD into two, which i guess is an isosceles? and i assure you that it is the only way of finding the shortest distance; connect it on the diagram for easier use.

Thanks sooo very much!!! I've been stuck on this for soo long! I'd be delighted to pay you back! Feel free to ask me if you need some help too
Oh and could also try Q10 v of this same paper plzz..

 

[Kshitij_2511]

Thanks sooo very much!!! I've been stuck on this for soo long! I'd be delighted to pay you back! Feel free to ask me if you need some help too
Oh and could also try Q10 v of this same paper plzz..

i'd be useless in helping you at sequencing

 

[Kshitij_2511]

use the quadratic equation by formula method
a = 2, b = -5, c = -6
x = -b(+or-) square root of [(b square)-4(a)(c)]/2(a)

 

[Ayeshah.ahmed]

quote="dubi2pro, post: 775153, member: 87748"]thanks for replying BRO! no worries! i swear when i saw ahmadumar quoted your post. i was like thank god!

no worries. still have some days for paper! [/quote]
dont you do IGCSE cie?my maths paper 4 is tomorrow when is yours?

 

[Ayeshah.ahmed]

yeah sequencing sucks big time!!!

 

[dubi2pro]

quote="dubi2pro, post: 775153, member: 87748"]thanks for replying BRO! no worries! i swear when i saw ahmadumar quoted your post. i was like thank god!

no worries. still have some days for paper!

dont you do IGCSE cie?my maths paper 4 is tomorrow when is yours?[/quote]
Ive got the same! :S

 

[dubi2pro]

actually that question was that of the retired IGCSE maths

 

[dubi2pro]

but still papers are still been taken for, these