MATHS (S1) j2003 Q5(iii)

[haris]

Q5. A committee of 5 people is to be chosen from 6 men and 4 women.In how many ways can this be done if :\
iii) there must be 3men and 2 women , and one particular woman refuses to be on the committee with one particular man?????? how should we do this part ......

 

[khizarr]

take these three possibilties:
both the man and woman are not in the committee : 5C3 * 3C2 = 30
the man is included, the woman isn't : 5C2 * 3C2 = 30
this time the woman is included: 5C3 * 3C1 = 30

total ways= 90