Mechanics 42

[Gooners]

the second part didn't hav constant speed!!!

Lol this is fr the first part! Part ii mai i did via ur method!!

 

[littlecloud11]

Cool i gt same answer but you know in the last part were we calculate force i used sin a instead of replacing it with 0.125 and my answer using sin a is 984936 and if replaced with 0.125 the answer wud be 985000 so its a bit near to that , will i lose marks? My method and angle was right except that I used sin a instead of replacing it with 0.125

1, i think.

 

[Saad Sarfraz]

you got a negative after integration. Dnt worry, it probably wnt b as bad as u think.
I hope I can salvage an A* InshAllah.

Thxx but not an A*..ill love an A

 

[littlecloud11]

Dang I forgot to add resistance to motion in the work done :/.... How many marks will I lose for that?

did you write the formula ryt? then you'll get the method mark. otherwise, 2 probably.

 

[littlecloud11]

Lol this is fr the first part! Part ii mai i did via ur method!!

your method has been verified by 'Most_Unique'

 

[JD REBORN]

Hey can someone tell me what was the value of t in 3b part and what was the distance?

 

[littlecloud11]

Hey can someone tell me what was the value of t in 3b part and what was the distance?

t= .896 and distance was 2.13m

 

[Saad Sarfraz]

As consant speed so force up the plane = force acting down the plane on object!!!!
800N + (12500Sin(7.18)) = 2362.33N
Now work = 2362.33 x 400 = 944934.5 = 945000J

Is mai 12500sin (7.18) is dwn the plane component!

Why didnt u add potential energy to it?

 

[JD REBORN]

t= .896 and distance was 2.13m

how was t=0.896

 

[littlecloud11]

how was t=0.896

you just had to use the calculator for this. t^(5/3)= 5/6 was already proved in the previous part, you just had to solve this to get the tym in part ii.

 

[AhmedNES]

WRONG!

did the same graph but did find the right answer who many marks i could get

 

[Most_UniQue]

1, i think.

Ahh no wayy!! thats unfair I used angle instead of replacing it ! WTH

 

[littlecloud11]

Ahh no wayy!! thats unfair I used angle instead of replacing it ! WTH

I knw. But i remember doing the same thing once and then checking the markscheme only to curse those cie ppl.

 

[shayreeikg]

what was the answer to question 2 ? where there was an angle..i think it was 53.1 and what was the tention ? i hope im not mixing up any of the questions

 

[Saad Sarfraz]

what was the answer to question 2 ? where there was an angle..i think it was 53.1 and what was the tention ? i hope im not mixing up any of the questions

Yep 5 was the tension and 53.1 was the angle!

 

[shayreeikg]

thanks ..and do you remember what question 4 was ?

 

[nafeekhan]

okay, I think Mechanics paper 42 was easy.
A good number of people in my hall found it easy like me.

I don't think it was as tough as Winter 2011 as ImaamMalik said.

However, I made one silly mistake.

in no. 6 i,

it is Fs = 800X400 + 1250X0.125X10x400.
= 945 000.

I forgot to multiply the mass by 10 ! .

will they cut the hwole 3 marks for that question or only one accuracy mark ?

DAMN I thought I could get a 100 in this paper .

 

[Gooners]

Why didnt u add potential energy to it?

I did so coz i didnt use the energy formula! I used the other method in which Force up the plane is equal to force down the plane! So no potential energy it!! Lol! Answer and concpt is right so INSHALLAH sahi hai! Many of my friends did via this method!!

 

[Gooners]

Yep 5 was the tension and 53.1 was the angle!

Yar Tension was 9N if i m nt wrong? :/

 

[Most_UniQue]

I knw. But i remember doing the same thing once and then checking the markscheme only to curse those cie ppl.

Hm I hate thisX(X(!!!

I did so coz i didnt use the energy formula! I used the other method in which Force up the plane is equal to force down the plane! So no potential energy it!! Lol! Answer and concpt is right so INSHALLAH sahi hai! Many of my friends did via this method!!

I did with your method Hi5!