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I dont remember. let me tryGuyz tension in Q2 was 9N na?
BINGO! I think it was 15cos53.1 which gives 9NGuyz tension in Q2 was 9N na?
angle was 53.1 and force i dnt remember properly but i guess it was 9Nguysss... what was the alpha angle in Q2 ? and the force ?
what was the question?ok and how to find the time in Q3 ii... and what was the final answer for time and distance plzz ??
ok so equation was v=t^5/3 +2 , replace v with 3 and find time . Then integrate velocity to get distance equation and plugin the time you found in first step...that was asking in part i to show that t^5/3 = 5/6
i did part i but i am not sure if i did part ii corrrect.. it was asking about distance of P from O when velocity is 3
i know we have shown that t^5/3 = 5/6 when velocity is 3 in part i
but how we can get the time from that equation ?
I dnt remember the equation properly v=t^5/3 properly but it was like this...ok so equation was v=t^5/3 +2 , replace v with 3 and find time . Then integrate velocity to get distance equation and plugin the time you found in first step...
I dnt remember as I said earlierin part i integrated acceleration to get v and i have put the upper and lower limits 3 and 2 and i showed that t^5/3 = 5/6
so what is v = t^5/3 +2 ?? from where did u get that 2 ?
you should integrate with the time t =0.89 you got from the t equation the put the limits from 0.89 to 0 this is going to get you 2.13
Im a 1thousand percent positive its 5. I think u made some sort of error caz my friend also got 9..Yar Tension was 9N if i m nt wrong? :/
No its 9 dude. F-15cos(53.1) which gives 9 N! There wasnt any force acting and the 12N force was vertical!Im a 1thousand percent positive its 5. I think u made some sort of error caz my friend also got 9..
yeah it was 9. one more confirmation.No its 9 dude. F-15cos(53.1) which gives 9 N! There wasnt any force acting and the 12N force was vertical!
tnx god So overall I lost only 9 marks which ws frm last questionyeah it was 9. one more confirmation.
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