Mechanics 42

[Gooners]

Guyz tension in Q2 was 9N na?

 

[Most_UniQue]

Guyz tension in Q2 was 9N na?

I dont remember. let me try

 

[Most_UniQue]

Guyz tension in Q2 was 9N na?

BINGO! I think it was 15cos53.1 which gives 9N

 

[Ramy]

guysss... what was the alpha angle in Q2 ? and the force ?

 

[Most_UniQue]

guysss... what was the alpha angle in Q2 ? and the force ?

angle was 53.1 and force i dnt remember properly but i guess it was 9N

 

[Ramy]

ok and how to find the time in Q3 ii... and what was the final answer for time and distance plzz ??

 

[Most_UniQue]

ok and how to find the time in Q3 ii... and what was the final answer for time and distance plzz ??

what was the question?

 

[Ramy]

that was asking in part i to show that t^5/3 = 5/6
i did part i but i am not sure if i did part ii corrrect.. it was asking about distance of P from O when velocity is 3
i know we have shown that t^5/3 = 5/6 when velocity is 3 in part i
but how we can get the time from that equation ?

 

[Most_UniQue]

that was asking in part i to show that t^5/3 = 5/6
i did part i but i am not sure if i did part ii corrrect.. it was asking about distance of P from O when velocity is 3
i know we have shown that t^5/3 = 5/6 when velocity is 3 in part i
but how we can get the time from that equation ?

ok so equation was v=t^5/3 +2 , replace v with 3 and find time . Then integrate velocity to get distance equation and plugin the time you found in first step...

 

[Most_UniQue]

ok so equation was v=t^5/3 +2 , replace v with 3 and find time . Then integrate velocity to get distance equation and plugin the time you found in first step...

I dnt remember the equation properly v=t^5/3 properly but it was like this...

 

[Ramy]

in part i integrated acceleration to get v and i have put the upper and lower limits 3 and 2 and i showed that t^5/3 = 5/6
so what is v = t^5/3 +2 ?? from where did u get that 2 ?

 

[Most_UniQue]

in part i integrated acceleration to get v and i have put the upper and lower limits 3 and 2 and i showed that t^5/3 = 5/6
so what is v = t^5/3 +2 ?? from where did u get that 2 ?

I dnt remember as I said earlier

 

[Ramy]

yea i know that.. u still didn't get my question.... i did part i correct but how to do part ii from the question ??

 

[sonamali]

i think it was 1.76m. was it?

 

[Ramy]

thnx alot bro

 

[Most_UniQue]

you should integrate with the time t =0.89 you got from the t equation the put the limits from 0.89 to 0 this is going to get you 2.13

Yh ryt

 

[Saad Sarfraz]

Yar Tension was 9N if i m nt wrong? :/

Im a 1thousand percent positive its 5. I think u made some sort of error caz my friend also got 9..

 

[Most_UniQue]

Im a 1thousand percent positive its 5. I think u made some sort of error caz my friend also got 9..

No its 9 dude. F-15cos(53.1) which gives 9 N! There wasnt any force acting and the 12N force was vertical!

 

[confused123]

No its 9 dude. F-15cos(53.1) which gives 9 N! There wasnt any force acting and the 12N force was vertical!

yeah it was 9. one more confirmation.

 

[Most_UniQue]

yeah it was 9. one more confirmation.

tnx god So overall I lost only 9 marks which ws frm last question