Mechanics M1: Post your doubt here

[Albert Einstein]

Hii...is the answer of the 1st part: 3.33 ms-2 ..!? Give me also the answer of the 2nd part.
Im doing the last part now...!!

its 4 the 1st part

 

[Amy Bloom]

Heyy can u give me the answers for the first part and second part too

sorry i wasn't there.

(a) h = 2.2​

(b) K.E = 1.6 J​

(c) ratio is root of (6/1.6)​

 

[Varuna0911]

so -F = ma
-0.12 = 0.15a
a= -0.8 m/s^2
v=u+at
v=3+(-0.8x2)= 1.4 m/s (velocity it arrives at Y)
at Y k.E = 0.5x0.15x1.4x1.4 = 0.147 J
it loses 0.072 J so k.E at Z = 0.147 - 0.072 = 0.075 J
0.5x0.15x(v^2) = 0.075
v = 1 m/s
since it is in the opp direction velocity becomes -1 m/s
at Z v= o
using v=u+at
0 = -1 + 0.8t
t = 1.25 s
it already took 2s to reach y
therefore total time taken = 2+ 1.25 = 3.25 m/s

thanks but do u know how the curve looks like?

 

[bamteck]

http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_w11_qp_42.pdf

HELP NEEDED for no. 7 (ii) (a) (b) (c)

 

[hussamh10]

Help me its quite urgent
View attachment 16720

First of all analyze the question this is hell of a question trust me
we hve to build two equation then solve the simultaneously (always consider this option if you cannot figure out the question)
so
the K.E at B =Mgh
mg(H-2.2)=1/2 x m x Vb

And then consider Whole journey from X till ground

mgH=1/2 x m x(2.55Vb)^2 Vg/Vb=2.55 so (speed at the ground)Vg=2.55^2

elimintate Vb by
1/2 x m xVb^2 =mg(h-2.2)
making Vb^2 the subject we get
Vb^2=20(H-2.2)
putting it in the second equation
1/2 x m x 2.55^(20(H-2.2))=10mH
By solving we get H=2.6 (i hope this is the answer by the way which paper is this?)

 

[hussamh10]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_42.pdf

HELP NEEDED for no. 7 (ii) (a) (b) (c)

You have to apply completing square here this tough question

 

[iKhaled]

but i left a question for 10 marks sooooo ... but i dnt think 45 i wish higher

nah man dont go so down like that 10 marks not 30 marks !!! so dw i hope u will hit a B or even an A in p1 god be with u isa

 

[iKhaled]

You have to apply completing square here this tough question

wow first completing the square question in mechanics i guess CIE r really changin the style of the questions !! i wonder whats gonna be new in tomorrow's paper..

 

[hussamh10]

wow first completing the square question in mechanics i guess CIE r really changin the style of the questions !! i wonder whats gonna be new in tomorrow's paper..

Yeah man

 

[iKhaled]

someone please draw the last graph!!7(ii) pleeeaseee

 

[daviruss]

wow first completing the square question in mechanics i guess CIE r really changin the style of the questions !! i wonder whats gonna be new in tomorrow's paper..

haha and the problem tht they award u only 2 to 3 marks

 

[GorgeousEyes]

iKhaled

someone please draw the last graph!!7(ii) pleeeaseee

 

[iKhaled]

iKhaled

y is it a parabola and not a straight line? isn't the velocity increasing with a constant rate ?​

 

[Mr Me]

iKhaled leadingguy Asheeta AhShun Mr Me Gunner7 hussamh10

I would like to thank you all for helping me , and I really appreciate your effort and caring . May allah reward you immensely . Good luck in your exam

Thanks you for appreciating our helps. Please pray for us. Good luck for you exams.

 

[Mr Me]

Can anyone please explain me the logic behind the part i.) of Q. no 5.
Why are we not taking the acceleration of one body as negative when they are traveling in opposite directions ?
Qp: http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s11_qp_42.pdf
Ms: http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s11_ms_42.pdf

Please reply soon if any one knows it and best of luck for your exams.

 

[daviruss]

Can anyone please explain me the logic behind the part i.) of Q. no 5.
Why are we not taking the acceleration of one body as negative when they are traveling in opposite directions ?
Qp: http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s11_qp_42.pdf
Ms: http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s11_ms_42.pdf

Please reply soon if any one knows it and best of luck for your exams.

 

[Mr Me]

View attachment 16742 View attachment 16742

Thanks for your working but I was asking why the acceleration of bodies don't have opposite signs ? I mean when they are in opposite directions shouldn't one be +ve and one -ve ?

 

[balay]

how was it guys?........didn't do last part of the last question......but other than that mine went really well....btw in q6(the one in which gain if k.e was needed) was speed at top like 58 or 59 m/s...?

 

[hussamh10]

how was it guys?........didn't do last part of the last question......but other than that mine went really well....btw in q6(the one in which gain if k.e was needed) was speed at top like 58 or 59 m/s...?

Speed at top was 20

 

[shikha95]

I messed up! I blanked out during the exam...