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obciously u have to find again mate as cooffecient depends on r and f if they chnge so will the coofficientguys i have a general question if in part 1 we are said to find the coefficient of friction of that surfacce will it remain the same even if we change the normal component and frictional force would we have to find the coefficient again if the normal component is changed??? iam really confused about this plzz help
So plz can u explain me this question
You are welcomethanks a million just got it
Nov10 p4 no 7(ii)
isnt the coefficent be changed beacuse normal component is changed why the same coefficent is used?
because it is on the same rough surface
alright thanx
Jun05 p4 no7
Jun12 p4 no7(i)
Thaaanks A looooot
could u plzz explain more
did nt rlly understand abt the triangles
1)P=Force x velocity
1)P=Force x velocity
now to find out the drivingforce when speed is 10ms
20Kw/10=2000N
Now we have to find the acceleration
RESULTANT force=Mass x Acc
Driving force -Resistiance =Mass x Acc
Acc=2000-500/12000
Acc=1.25
2)Total work done =(500 x D)+(.5(1200) x(25^2-10^2)
Power=Work done/Time
so we get
20000x30.5=500d+315000
By solving we get
d=590
Hope i helped
Is it the answer?
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