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9702_s06_1
q9,24,26,34
THX ALOTTTT!
q9,24,26,34
THX ALOTTTT!
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need a help for physics....!
- Thread starter supermagic
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Q9: you can do this question if you have an idea of Simple Harmonic Motion !
when the mass is at its lowest point or back to the mean position, displacement is minimum while velocity is maximum... Velocity is maximum at B and D, but since they ask for the lowest point, answer is D !
Q24: Half the means that the graph is either A or B , but intensity is directly proportional to (amplitude)^2 ... so the amplitude won't double but would be 1.4a ...
Q26: In a standing wave, vibrations occur at all points b/w the nodes and the vibrations are in phase...
Q34: Draw a circuit diagram for better understanding! use potential divider rule to find voltage across heater...
V = {3 / (3+1) } x 12 = 9V
P = V^2 / R = 9^2 / 3 = 27W !
Hope u get that
when the mass is at its lowest point or back to the mean position, displacement is minimum while velocity is maximum... Velocity is maximum at B and D, but since they ask for the lowest point, answer is D !
Q24: Half the means that the graph is either A or B , but intensity is directly proportional to (amplitude)^2 ... so the amplitude won't double but would be 1.4a ...
Q26: In a standing wave, vibrations occur at all points b/w the nodes and the vibrations are in phase...
Q34: Draw a circuit diagram for better understanding! use potential divider rule to find voltage across heater...
V = {3 / (3+1) } x 12 = 9V
P = V^2 / R = 9^2 / 3 = 27W !
Hope u get that
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dat was quick!!! and thzx alott!
but i dun understand Q24, i no it's either A or B but since intensity is proportional to (amplitude^2) and ( frequency^2)
so shoudlnt the answer be A???? becuz it has double intensity, and half frequency,
2 I(intensity) = A^0.5 * F^0.5
2 = A^0.5 * (0.5F)^0.5
A^0.5 = 4 so... amplitude is 2....?
but i dun understand Q24, i no it's either A or B but since intensity is proportional to (amplitude^2) and ( frequency^2)
so shoudlnt the answer be A???? becuz it has double intensity, and half frequency,
2 I(intensity) = A^0.5 * F^0.5
2 = A^0.5 * (0.5F)^0.5
A^0.5 = 4 so... amplitude is 2....?
- Messages
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Let's take it this way...
since intensity is proportional to (amplitude^2) ...
I / a^2 = I /a^2
I/a^2 = 2I / x^2 ....... ( x is the new amplitude )
solve it...
x = 1.4a
if we assume "a" to be 1 unit... then 1.4 x 1 = 1.4 units... and that is exactly seen in graph B !
since intensity is proportional to (amplitude^2) ...
I / a^2 = I /a^2
I/a^2 = 2I / x^2 ....... ( x is the new amplitude )
solve it...
x = 1.4a
if we assume "a" to be 1 unit... then 1.4 x 1 = 1.4 units... and that is exactly seen in graph B !
gravitaional ques prob!!
Q1,find the speed of the satellite which orbitz the moon near the moon's curface?
what is the kinetic energy per unit mass of the satellite?
(radius of moon: 1.74*10^6,mass of moon: 7.35*10^22)
Q2,astronomical observationz show the centre of mass of the earth-moon system is 4.7*10^6 m frm the centre of the earth.the distance b/w the centre of the earth n the moon is 384.4*10^6 m.find the mass of the moon M in terms of the mass of the earth E.
explain why both earth n moon must rotate about their common centre of mass,rather than the moon abot the centre of mass of the earth.
Q1,find the speed of the satellite which orbitz the moon near the moon's curface?
what is the kinetic energy per unit mass of the satellite?
(radius of moon: 1.74*10^6,mass of moon: 7.35*10^22)
Q2,astronomical observationz show the centre of mass of the earth-moon system is 4.7*10^6 m frm the centre of the earth.the distance b/w the centre of the earth n the moon is 384.4*10^6 m.find the mass of the moon M in terms of the mass of the earth E.
explain why both earth n moon must rotate about their common centre of mass,rather than the moon abot the centre of mass of the earth.