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Need mole question explanation

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The equation for the reaction between calcium carbonate and hydrochloric acid is shown.
CaCO3(s) + 2HCl(aq) → CaCl 2(aq) + H2O(l) + CO2(g)
How many moles of calcium carbonate will give 24 cm3
of carbon dioxide when reacted with an
excess of the acid?
(Assume one mole of carbon dioxide occupies 24dm3.)
A 1mol B 0.1mol C 0.01mol D 0.001mol
 
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The equation for the reaction between calcium carbonate and hydrochloric acid is shown.
CaCO3(s) + 2HCl(aq) → CaCl 2(aq) + H2O(l) + CO2(g)
How many moles of calcium carbonate will give 24 cm3
of carbon dioxide when reacted with an
excess of the acid?
(Assume one mole of carbon dioxide occupies 24dm3.)
A 1mol B 0.1mol C 0.01mol D 0.001mol


change the units of the green ones to dm3....... maybe this can help?
 
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The equation for the reaction between calcium carbonate and hydrochloric acid is shown.
CaCO3(s) + 2HCl(aq) → CaCl 2(aq) + H2O(l) + CO2(g)
How many moles of calcium carbonate will give 24 cm3
of carbon dioxide when reacted with an
excess of the acid?
(Assume one mole of carbon dioxide occupies 24dm3.)
A 1mol B 0.1mol C 0.01mol D 0.001mol

yes first change the cm3 to dm3 or vice versa.. then find the number of moles of CO2 that will be produced (24/24000 = 0.001 moles, I converted 24 cm3 to dm3)... since the acid is in excess or the CaCO3 is the limiting reagent, we will be taking into account only CaCO3 for calculations. Since the mole ratio of CaCO3 and CO2 is 1:1, moles of CaCO3 is 0.001... thus answer is D
 
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correct answer is D
the equation shows that 1 mole of CaCO3 gives 1 mole of CO2. Now it is given that 24cm3 of CO2 is obtained. We will see that how many moles are there in 24cm3 of CO2.
Moles in 24cm3 of CO2: 24/24000=0.001 (formula: moles=volume/molar gas vol,i.e fixed at 24dm3 or 24000cm3)
thus if 1 mole of Calcium Carbonate gives 1 mole of Carbon dioxide. then 0.001 moles of CO2 are obtained from 0.001 moles of CaCO3
 
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