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nothingngngng

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The value had to be found by deviding the mean moles of H2O / Mean mass of BaCl2??? tell me yeS!!!
 
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What was x?
N i messed up last part of titration the relative formula mass i just couldnt get it
 
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The value had to be found by deviding the mean moles of H2O / Mean mass of BaCl2??? tell me yeS!!!

We know the mean number of mols of water
And we also calculated the mean "mols" of BaCl2 (mean mass of BaCl2/ RFM of BaCl2)
Therefore

For example ,
Mean moles of water = 0.006
Mean moles of BaCl2 = 0.003

BaCl2.xH2O

So we have to find how many moles of water for 1 mol of BaCl2
=> 0.003 mols of Bacl2 - 0.006 mols of water
Hence 1 mole gives 0.006/0.003 = 2
 
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We know the mean number of mols of water
And we also calculated the mean "mols" of BaCl2 (mean mass of BaCl2/ RFM of BaCl2)
Therefore

For example ,
Mean moles of water = 0.006
Mean moles of BaCl2 = 0.003

BaCl2.xH2O

So we have to find how many moles of water for 1 mol of BaCl2
=> 0.003 mols of Bacl2 - 0.006 mols of water
Hence 1 mole gives 0.006/0.003 = 2

mine was 0.007 and 0.002 or smthng the ratio was 2.83:confused:
 
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