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i got 388
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i got the sameWid fe2+ it was Nh4+ n SO4^2-
N da others were chromate lead and carbonate
1:2 so 2H2Osame here
what about that ratio of bacl2 and h20
The value had to be found by deviding the mean moles of H2O / Mean mass of BaCl2??? tell me yeS!!!
with fe2+ , i got Nh4+ and so42-
We know the mean number of mols of water
And we also calculated the mean "mols" of BaCl2 (mean mass of BaCl2/ RFM of BaCl2)
Therefore
For example ,
Mean moles of water = 0.006
Mean moles of BaCl2 = 0.003
BaCl2.xH2O
So we have to find how many moles of water for 1 mol of BaCl2
=> 0.003 mols of Bacl2 - 0.006 mols of water
Hence 1 mole gives 0.006/0.003 = 2
That's totally fine I was just giving an examplemine was 0.007 and 0.002 or smthng the ratio was 2.83
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