- Messages
- 38
- Reaction score
- 17
- Points
- 18
Q3:
n=50/2x(23+3x14) [2x because there are 2 moles NaN3.]
n= 5/13
3n=V/24 [3x because there are 3 moles of N2.]
3x5/13 x 24 =V
27.69 = V
The answer is (C) which is 27.7
Q9:
One molecule of HCl dissipates one H+ ion. Now looking at the options:
(A) Ethanoic Acid [It is weak acid and cannot dissipate the H+ ion completely.]
(B) Nitric Acid [The formula is HN)3. Each molecule can dissipate one H+ ion, same as HCl.]
(C) Sodium Hydroxide [It doesn't even dissipate H+ ion!!.]
(D) Sulphuric Acid [H2SO4 dissipates 2 H+ ions per molecule, twice that of HCl.]
So the answer is (B),
Q18: [I couldn't do it. Will try again soon.]
Q37:
1 All bond angles are approximately 120o. [This is true. I hope you know why.]
2 It will undergo electrophilic addition reactions. [Yes they undergo electrophlic addition because of presence of double bonds.]
3 It will undergo nucleophilic addition reactions. [Yes they undergo nucleophlic addition because of presence of lone pairs on Oxygen.]
So answer is (A).
Q39:
First of all, alkanes are not soluble. Arene rings are alkanes which aren't soluble. This gives direct answer of option 1 being correct. Option 1 is a Aldehyde which are oxidized to Carboxylic acids, which are quite soluble! So answer is (D).
Note: Option 2 is also an aldehyde and form a carboxylic acid but with poor solubility due to presence of arene ring. Option 3 is a Ketone and cannot be easily oxidized further.
(If I'm wrong somewhere, please correct me. I got my answers this way which are all correct.)
Can u plz help me with these MCQ's of May/June 2002
2, 4, 5, 6, 7, 8 and 23.
I'll b really greatful.