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But all we need to know is that with the removal of one H, the C gains a +ve charge. Is that right?
Yes it is.
Thanks anyways.
And referring to my question its may/ june 2012
Thanks.
MJ/12/qp11 Q14 was daunting.
Let's form the equation first.
Al + Ba(NO3)2 ---> Al2O3 + BaO + N2
They said only metal oxides and Nitrogen is produced hence the above.
Balance it. (This balancing was slightly cumbersome)
Anyway:
I got:
10/3 Al + Ba(NO3)2 -------> N2 + BaO + 5/3 Al2O3
Multiply be 3:
10Al + 3Ba(NO3)2 ----------> 3N2 + 3BaO + 5 Al2O3
...............3(261) ......................3(28)
................783............................ 84
..............0.783........................... x
x = 0.783 * 84 / 783 = 0.-84 g N2
Convert it into moles:
0.84/28 = 0.003mol
Find volume.
0.003 * 24000 = 72 cm3