• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

p3 maths

Messages
2,884
Reaction score
415
Points
93
doubt in vecotr question
june 09
q9
ii
i know to solve vector
but this one.......i dont get the ans
 
Messages
55
Reaction score
0
Points
0
Well, this is how i attempted it.
i put t=0 in the eq of line.....and put the point in the plane eq.
forming an eq in terms of b and c.
then i took the dot product of normal to the plane and the directional vector of the line and put it =0
so i got another eq relating b and c..
then i solved them simultaneously....
part ii is simple..so i didn't attenpt it..but i think it could be done like this...you calculate AP....assuming A is a point where t=0
find the vector product of AP and the directional vector of l.
then take the modulus of this new found vector and divide it by the modulus of the directional vector. i dont knw the answer but try it, i think it will yield the right answer. hope this helps..
 
Messages
55
Reaction score
0
Points
0
i just solved it....first find AP=OP-OA
then take the cross product of AP and directional vector of l
take the modulus of the answer
and divide it by the modulus of directional vector..
it wud be something like...underroot 45 over underroot 9...
 
Top