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PHY MCQ w09 problems

T

TSZ

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applepie1996

applepie1996

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TSZ said:
hey guys, cn u please help with te following questions of oct 09 phy ppr 1
Q6, Q9, Q13, Q14, Q15, Q17, Q19, Q22, Q27, Q28. Please I'm really worried. I used to post my questions on those specific threads but no one answers me on them, i've tried that 4 or 5 times. Please help.
qp: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_qp_11.pdf
ms: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_ms_11.pdf
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q6)the answer is displacement because the only think that increases and decreases lyk dat is height

q9)first thing they dunt stick together so that cuts D
momentum b4 collision=momentum after collision
so 2m x u - m x u =mu so mu is the momentum b4 collision now from all the options given the only option that gives us mu after collision is A
check it

Q13) u first find the tension at the top of the belt tension is a force so torque=one of the two forces x distance between then so force =3/100 x 10^-3=30N
total tension is 30 x 2 cuz u have to take one of the two forces to find torque but we need the total
then torque of P=30N(one of the two forces) x 150 x 10^-3=4.5

q14)ok over here u assume mass of ball = 2kg and initial speed =10m/s
now find E=1/2 x 2 x 10^2=100J
it is thrown at an angle of 45 degree so now u find the new velocity =sin 45 x 10 =7.07m/s
find new ke=1/2 x 2 x 7.07^2=50J
so 50/100=1/2 so ans=E/2

15))momentum b4 collision= momentum after collision
so b4 collision they were stationary so momentum =0
0= 2 x 2 + 1 x v
v=4m/s
so now v found the speed at wich the 1kg trolley moves
find KE OF BOTH 1/2 x 2 x2^2- (-1/2 x 2 x4^2)=12J

Q19) u use pressure = height x density x g so 15200=0.8m x d x 9.8 so d=1938

Q22) u first find area i hope u noe dat=1.96 x 10^-7m^2
then YOUNG MODULUS=stress/strain
find strain from the given values u get 5.1 x 10^-4 this is equal to e/l of which we have to find the % so just multiply by 100 u get the answer
 
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