Physic Help

[salmanhassan]

I got Problem In
1(C)(B)
2(B)
how to solve it ??
Anyonee !!

 

[Hamzeh S]

For part C first questions just take any 2 points from y axis and divide them by difference between any 2 points at x-axis the answer would be 5.71 something like that in part B when you draw the best fit line and extend it the point where it touches the y -axis is the point where acceleration is equal to 0
the seconds part nothing happens because the force which is higher didnt affect it so the lower force wont affect it also

for questions 2 lemme read it

 

[Hamzeh S]

well we got the power which 528 multiply it by the time which is 5 to get the energy or workdone in Joules
2640 = force x distance in meters
2640 = 800 x D
D = 3.3 meters x100 = 330 CM each rug is 30 cm so 330/30 is equal to 11 rugs
Post Any more doubt if you need

 

[salmanhassan]

Thankss Alt May god bless you =)
Dude this same paper Qeustion 3 (B) iii one ??
this paper seem hard ...

 

[Hamzeh S]

Use the law of pressure 1 x volume 1 = pressure 2 x volume 2
so 2.2x10^5 x 0.5 = V2 x atomosphereic pressure since its gonna reach the surface so


110,000=V x 1x10^5

v= 110000/1x10^5
=1.1 cm3

 

[thats_me]

MJ 11 var 31 ques 2 c hwz it done?

 

[salmanhassan]

Use the law of pressure 1 x volume 1 = pressure 2 x volume 2
so 2.2x10^5 x 0.5 = V2 x atomosphereic pressure since its gonna reach the surface so


110,000=V x 1x10^5

v= 110000/1x10^5
=1.1 cm3

ohh i used it buh i puted the value wrong
Thanks Mate