Physics 12 GT

[Princess Raven]

I did the ball one 3 times it was C..

Who knows? I could be wrong, but the resistor HAS to get some P.D. cause it does have resistance.



I got B for the ball one. Anyone else?

 

[Princess Raven]

Guys no need to worry about this paper at all, if you do good in papers 2 n 3 you still end up with an A cuz they take the avg of the papers ( I have a friend who messed up like 30/120 marks in IG Maths p4 and still ended up with A*)

Um how is ig p4 and physics p1 even related lol

 

[Rohan O]

Guys did anyone put condensation for the process

I put evaporation

 

[Kamihus]

Who knows? I could be wrong, but the resistor HAS to get some P.D. cause it does have resistance.



I got B for the ball one. Anyone else?

The first voltage was of the first resistor
The second one was of the one in parallel
By 8V I mean the emf of the battery, it was either 8V or 5V but don't remember exactly
I got A for the ball one but I'm probably wrong

 

[Omar Haider]

I remember it was q I guess do you which option was that?

Q was B Because they put options P, Q, R and (D) was none of these, I think. Q was the one with 2.0 m/s right?

 

[Rohan O]

Q was B Because they put options P, Q, R and (D) was none of these, I think. Q was the one with 2.0 m/s right?

Sorry it was R I suck at memorizing things:/ I calculated that like 2 times and it was R

 

[Princess Raven]

YES

Sorry it was R I suck at memorizing things:/ I calculated that like 2 times and it was R

THANK U! It wasn't r btw it was s r wasn't even an option lol

 

[Omar Haider]

I don't remember the question exactly, but what did you put for the potential divider question where we had to find the resistance of the resistor? Options were like 755, 855, 955 and 1055 I think

 

[Snowysangel]

Who knows? I could be wrong, but the resistor HAS to get some P.D. cause it does have resistance.



I got B for the ball one. Anyone else?

Yup me. Wait didnt the resistances add up to 8V when the PDs were 3V and 2V...the last resistor also had to be 3V and 3+3+2=8V no?

 

[Snowysangel]

I don't remember the question exactly, but what did you put for the potential divider question where we had to find the resistance of the resistor? Options were like 755, 855, 955 and 1055 I think

I didn't understand that question at all...I think I marked the 800 one

 

[Omar Haider]

Yup me. Wait didnt the resistances add up to 8V when the PDs were 3V and 2V...the last resistor also had to be 3V and 3+3+2=8V no?

Yes, however there was also a resistor, so that takes up P.D. as well. And if one resistor in parallel already has a P.D. of 1 V then how will the others have 3? Voltage is the same in parallel.

 

[Kamihus]

Yup me. Wait didnt the resistances add up to 8V when the PDs were 3V and 2V...the last resistor also had to be 3V and 3+3+2=8V no?

Yup that's my point but I don't even remember the question exactly

I don't remember the question exactly, but what did you put for the potential divider question where we had to find the resistance of the resistor? Options were like 755, 855, 955 and 1055 I think

I did 795 or something like that

 

[Omar Haider]

I didn't understand that question at all...I think I marked the 800 one

Yup, I guessed the same as well *high five*

 

[Princess Raven]

I don't think those were the

I don't remember the question exactly, but what did you put for the potential divider question where we had to find the resistance of the resistor? Options were like 755, 855, 955 and 1055 I think

options but I rmr first one was 395 and second was 795 I calculated it to be 795 so I chose B

 

[Snowysangel]

Sorry it was R I suck at memorizing things:/ I calculated that like 2 times and it was R

Wait wait gain in kinetic energy was equal to the loss in potential energy...and it lost 1/4th of its potential energy when it gained 1/4th of its kinetic energy so .5*4*4=8 and 1/4th of that is 2J which is equal to .5*2*2 so that's why I marked B

 

[Kamihus]

Yes, however there was also a resistor, so that takes up P.D. as well. And if one resistor in parallel already has a P.D. of 1 V then how will the others have 3? Voltage is the same in parallel.

The one in parallel had 1V and there was another with the same with series with it so it also was 1V. Total 2V and parallel to them would be 2V too. I don't remember how many more resistors there were

I don't think those were the

options but I rmr first one was 395 and second was 795 I calculated it to be 795 so I chose B

I calculated 800 so just wrote 795

 

[ijlalm]

it was D(none of the above)?

 

[Kamihus]

Wait wait gain in kinetic energy was equal to the loss in potential energy...and it lost 1/4th of its potential energy when it gained 1/4th of its kinetic energy so .5*4*4=8 and 1/4th of that is 2J which is equal to .5*2*2 so that's why I marked B

I did it as A, B was point Q or point R?

 

[Snowysangel]

Yes, however there was also a resistor, so that takes up P.D. as well. And if one resistor in parallel already has a P.D. of 1 V then how will the others have 3? Voltage is the same in parallel.

Yeah so in the parallel circuits there were 2 in one loop and 1 in the other so the total potential energy was 2V right? But them there were two more resistors (in series with each other) and if they were both equal to 3V the total pd could be 8V

 

[Snowysangel]

I did it as A, B was point Q or point R?

Second one