physics 22

[Muhammad Haris Ghani]

Let's just focus on paper 1 now. I have forgotten paper 2 already.
Believe me or not but we did this question wrong. Ask your teacher. I hope I get an A too IA. So worried.

you ask your teacher and then inform me w=fx is only used when f is constant

 

[rabos1]

you ask your teacher and then inform me w=fx is only used when f is constant

You ask your teacher because I'm sure we are wrong.. acc wasn't constant..

 

[Muhammad Haris Ghani]

You ask your teacher because I'm sure we are wrong.. acc wasn't constant..

ok I agree that wasnt constant but you cannot use w=fx because that only can be applied when force is constant you ask your teacher and I challenge all who used w=fx that they are wrong and I can prove that w wasnt constant because ke was changing yar come on yar

 

[rabos1]

ok I agree that wasnt constant but you cannot use w=fx because that only can be applied when force is constant you ask your teacher and I challenge all who used w=fx that they are wrong and I can prove that w wasnt constant because ke was changing yar come on yar[/quote

it was constant. Force was increasing uniformly and plus we were supposed to subtract frictional force and then use w= fxd

 

[I don't care]

ok I agree that wasnt constant but you cannot use w=fx because that only can be applied when force is constant you ask your teacher and I challenge all who used w=fx that they are wrong and I can prove that w wasnt constant because ke was changing yar come on yar

i didn't mention anything about w=fx the only way to correctly do the question is to take the area under the graph which is energy and the total energy possessed by the truck is 1.3 j 1.3=1/2 * 14* pq

 

[sam1234]

you ask your teacher and then inform me w=fx is only used when f is constant

There's got to be a way, If you say this is wrong, than what do you propose is the correct solution for the question? :O

 

[Muhammad Haris Ghani]

i didn't mention anything about w=fx the only way to correctly do the question is to take the area under the graph which is energy and the total energy possessed by the truck is 1.3 j 1.3=1/2 * 14* pq

Let me tell you that the speed was slowing and so the kinetic energy so how can you use 1.3 as w

 

[Muhammad Haris Ghani]

There's got to be a way, If you say this is wrong, than what do you propose is the correct solution for the question? :O

a=f/m gives you the deceleration and then 2as=v2-u2 where initial velocity was 2.4 mentioned in the question itself and final velocity 0ms as the trolly at q becomes at rest

 

[Muhammad Haris Ghani]

i didn't mention anything about w=fx the only way to correctly do the question is to take the area under the graph which is energy and the total energy possessed by the truck is 1.3 j 1.3=1/2 * 14* pq

bro ask your teacher he will make your concept clear and yes inform me as well

 

[sam1234]

a=f/m gives you the deceleration and then 2as=v2-u2 where initial velocity was 2.4 mentioned in the question itself and final velocity 0ms as the trolly at q becomes at rest

What will be f equal to in that case? F was constantly changing? I wonder if you have an answer for that too.

 

[DumbIdiot]

value of PQ got to be .18
work can be done to increase or decrease energy of a particle in a system.
an example of decrease of energy would be a braking truck.
frictional force opposes the motion of the truck and decreases its kinetic energy
we`ve got to use area under graph in this question

friction is always opposing motion but we still say "workdone by frictional force".

 

[Ujjwal Basnet]

value of PQ got to be .18
work can be done to increase or decrease energy of a particle in a system.
an example of decrease of energy would be a braking truck.
frictional force opposes the motion of the truck and decreases its kinetic energy
we`ve got to use area under graph in this question

friction is always opposing motion but we still say "workdone by frictional force".

cant we find change in ke the use the formula of wd=ke or f*d=k.e?

 

[Muhammad Haris Ghani]

What will be f equal to in that case? F was constantly changing? I wonder if you have an answer for that too.

First tell me how you find the distance

 

[Muhammad Haris Ghani]

value of PQ got to be .18
work can be done to increase or decrease energy of a particle in a system.
an example of decrease of energy would be a braking truck.
frictional force opposes the motion of the truck and decreases its kinetic energy
we`ve got to use area under graph in this question

friction is always opposing motion but we still say "workdone by frictional force".

then at that case you will have to subtract frictional opposing force which wasnt possible my was 0.089m which everyone almost got at my centre

 

[sam1234]

First tell me how you find the distance

Loll, are you asking me? you are just arguing on a pointless argument. Go ask your teacher now.

 

[Muhammad Haris Ghani]

Loll, are you asking me? you are just arguing on a pointless argument. Go ask your teacher now.

Hahaha... you should give up your A level because all your concept seems to be illogical bro I will offer you to ask your teacher and clear all your doubts and concepts

 

[Muhammad Haris Ghani]

You ask your teacher because I'm sure we are wrong.. acc wasn't constant..

What was your unit for C...

 

[Muhammad Haris Ghani]

Loll, are you asking me? you are just arguing on a pointless argument. Go ask your teacher now.

And yes what was your power for wires and your unit for C ....

 

[sam1234]

Hahaha... you should give up your A level because all your concept seems to be illogical bro I will offer you to ask your teacher and clear all your doubts and concepts

Whatever makes you sleep at night. Kbye.

 

[sam1234]

And yes what was your power for wires and your unit for C ....[/quote

Since you believe only you have the right concepts, why don't you go first in telling your answers for the power and units for C? I bet your teacher must have taught you the CORRECT concepts?