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@ PhotoHuman, At max height V(horizontal) was still present.. so i figured that max Ep(11) would be less than max Ek(15)?At maximum height, all of the kinetic energy is converted to potential energy.......this is also the law of conservation of energy.
So u can also check with that....if ur maximum kinetic energy equals ur maximum potential energy then your answer would be correct.
But for me the maximum height was 1.77 and the KE and PE both were 11.3
The graph represented VERTICAL COMPONENT of velocity, initial was 6. Unknown h was the maximum height possible, where vertical component turns to zero. Using the equation, v2- u2 = 2aS, we get (6)^2= 2 x 9.81. x H, and that turns out to be 1.83.How was the max height 1.80m? Values kya daleen?
Sorry, but it was mentioned it is the vertical component of velocity. H was 1.8, this is for sure.'v' was not the vertical component of velocity. The speed with which the ball was set into motion was 'v'. Diagram pr labelled tha. :/
Are U sure that therholds r lower plzzzzzzzz tell.....Usually for Oct/Nov the grade tresholds are lower........I mean lower than 40...but this paper was kind of, and I repeat, KIND OF easy
Do you not check the grade thresholds?Are U sure that therholds r lower plzzzzzzzz tell.....
never said anything about vertical velocity, it said that it was projected with V 6ms'v' was not the vertical component of velocity. The speed with which the ball was set into motion was 'v'. Diagram pr labelled tha. :/
well it was a projectile motion so the horizontal velocity was there even if vertical velocity was zero.. so all the k.e was not converted to p.e as there was still some k.e due to horizontal velocity..At maximum height, all of the kinetic energy is converted to potential energy.......this is also the law of conservation of energy.
So u can also check with that....if ur maximum kinetic energy equals ur maximum potential energy then your answer would be correct.
But for me the maximum height was 1.77 and the KE and PE both were 11.3
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