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Physics 9702 Paper 5 Planning and Experiments

Wasim Mohammed

Wasim Mohammed

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As requested :
Things to list out in Paper 5 question 1:

1)What are the variables(3 marks)
-Change _____ to determine/find ____
_____ should be kept constant (control)
-Independent Variables=
-Dependent Variable=
-Control=

2) Labelled Diagram of apparatus used (5 marks)
How do u measure the variables?
(Equipment used , Equation needed to calculate , things to watch out when taking measurements (eg.zero error) )
How do you keep control variable constant ?
(check using___ .. Not moved____ )
How is the experiment carried out ?
Repeat for difference, for plotting graph

3) How is the data Analyzed ? (2 marks)
Show how to express equation as y=mx+c
Explain what to plot :
Plot____on y-axis and ___on x-axis.
Read Question, What you need to do ?
Prove relationship : If relationship is true, a straight line with gradient =_____ & y-intercept=_____ should be obtained.
Calculate constant:
A straight line with gradient : ____ & y-intercept : _______ should be obtained .

Show how you calculate constant from gradient/y-intercept

4)What are the Dangers & Safety Precautions ? (1 mark)
(eg, fire , loads, high voltage, sharp)

5) Additional Details (4 marks)
Anything you need to tell the experimenter

Hope this helps in your preparation for paper 5
If you guys need details of certain experiments , pls drop down a comment
Would Love to see your comments and feedbacks on this :D
 
Wasim Mohammed

Wasim Mohammed

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abdul moeed rana said:
need notes for q 2?how to draw worst acceptible line,errors,error bars,etc.all noes for q2,please help and post soon
Click to expand...

Can't really help you on Question2 , but i will try :D

So here it is. Usually question 2 ,
Experess equation in y=mx + c form and find gradient and y-intercept

the Table then
You have to label the table with the quantity(using Symbol given) & unit
E.g. L/m
(lg , ln , cos , sin , tan has no units)
So whenever it is with lg, for example , it must be like eg. lg(L/m)
Absolute error = Best value of quantity calculated - Worst value of quantity calculated (Biggest/smallest)
Example : if a= (12.1 +/- 0.1 )
To find a^2 with its error :
1) Best value of a^2 = (12.1)^2=146.41
Worst value of a^2= (maximum a)^2 = (12.1+0.1)^2 = 148.84
or (minimum a)^2 = (12.1-0.1)^2 = 144.0
Error in a^2= 148.84 - 146.41 = +/-2.43
or 144-146.41= +/- 2.41
Error in a (always 1 sig.fig) = +/- 2
Best value must have same no. of d.p as error

Note:-
For lg & ln quantities , the final answer is expressed as the same no. of decimal places(or/more) as the no. of s.f in the raw value
Eg . If c= 15 ( 2 s.f.)
lg c = 1.17609...
Hence lg c can be expressed as 2 or 3 d.p
lg c= 1.176 or 1.18
When calculating error(for 2 or more quantities with error) , be careful when finding worst value :-
E.g a= (10.1 +/- 0.1)
b= (21.1 +/- 0.1)
Worst value of ab = (max a)(max b)
or (min a)(min b)
Worst value of a/b = (max a/min b) or (min a/max b)

Plotting a graph
Normal rules:-
-Plot and read to 1/2 a square (using x is preferable to mark the point)
-Plot points
-Label & Draw best fit line.
-Plot error bars :-
If on Y axis ( then vertical)
If on X axis ( then horizontal)

- Plot & label worst fir line which is the steepest/shallowest line passing through all error bars. ( which is the last point on error bar on last plot and the first point on error bar on first plot or vice versa)

To find gradient & error :-
1) Find gradient of best fit line
2) To find the errors:-
-Find gradient of worst fit line
Error in gradient= |Gradient of best fit line - Gradient of worst fit line |
Final answer : ( gradient +/- error in gradient ) (keep to same d.p. for both)

To find Y-intercept & errors :-
1) Find y-intercept of best line ( Read from graph if x starts from 0)
or calculate using y=mx + c
To find error:-
Find y intercept of worst line
Error in y-intercept = Cbest - Cworst

Analysis
Error calculation still based on general rule:
Error=Best value - Worst value
Calculate error only if eqn. asks for it.
Know how to calc. % uncertainty -
% uncertainty = Error/best value x 100%
Express answer in appropriate precision (include units if asked)


I hope this helped, this notes took me quite a while to prepare
If in need of any clarification pls do ask ,
Again if any comments or feedbacks pls do so. :)
 
Zachary Adrian

Zachary Adrian

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Hello everyone. Thanks for all the shared information, really appreciate it :) I have a question about Paper 5, question 1. When drawing out a diagram for your experiment, does your drawing have to actually look like the apparatus? For example, there was a question about light intensity and it required the use of a photocell. If I didnt know what a photocell looked like, could I just draw a box or something and label it photocell?
 
Wasim Mohammed

Wasim Mohammed

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Zachary Adrian said:
Hello everyone. Thanks for all the shared information, really appreciate it :) I have a question about Paper 5, question 1. When drawing out a diagram for your experiment, does your drawing have to actually look like the apparatus? For example, there was a question about light intensity and it required the use of a photocell. If I didnt know what a photocell looked like, could I just draw a box or something and label it photocell?
Click to expand...
Yeah , that's fine , SO long as it's not too weird. U can just draw something, and label it as photocell bcos they can't deny its not a photo cell , bcos u already labelled it.
 
Zachary Adrian

Zachary Adrian

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I have another rather silly question that I would really appreciate help with... If for example, a graph of pressure/10^5 Pa is plotted against (1/height)/m^-1..... When calculating the gradient, do we have to multiply the y coordinates with 10^5? So it would be gradient= [ (Y2-Y1)x 10^5]/ [X2-X1] ??
 
Wasim Mohammed

Wasim Mohammed

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Zachary Adrian said:
I have another rather silly question that I would really appreciate help with... If for example, a graph of pressure/10^5 Pa is plotted against (1/height)/m^-1..... When calculating the gradient, do we have to multiply the y coordinates with 10^5? So it would be gradient= [ (Y2-Y1)x 10^5]/ [X2-X1] ??
Click to expand...
Yup u have to multiply .. bcos if u don't , the calculation of the uncertainty can be wrong.. and it's just overall better ! hahah :D
 
Zachary Adrian

Zachary Adrian

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Wasim Mohammed said:
Yup u have to multiply .. bcos if u don't , the calculation of the uncertainty can be wrong.. and it's just overall better ! hahah :D
Click to expand...
You my friend are awesome. Thank you so much! So many people on this site have been asking this question but no one seems to be certain on the answer. God bless you :D
 
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