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So this is one of the solved questions : May june 2013 p52 Question 1 paper that i did. I have attached it below. I hope u guys find this useful . And again if any comments or feedbacks pls do so .
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where is it i cant find itSo this is one of the solved questions : May june 2013 p52 Question 1 paper that i did. I have attached it below. I hope u guys find this useful . And again if any comments or feedbacks pls do so .
Correction : If a straight line graph not passing through the origin is obtained , this prove relation that (V0/I0)^2 = (4Pi^2 x L^2)(f^2) + R^2
for 1st 18.9/10 for the value of T and 0.1/10 for the uncertainity of TPlease can u solve mj 10 var53 question 2......and upload it
Here's the solved paper..Please can u solve mj 10 var53 question 2......and upload it
thank you very muchA hard paper indeed. Oct/Nov/2009 P51 Question 2 . I have attached the pdf file below Hope this helps u guys .AND thanks to emma for suggesting the paper
thank you very much
And don't the best and worst line have to touch the lower and upper ends of the graph?
thanx a lot for solved papers can u pls solve Q1 of paper 5Ur welcome and yeah (they Have to pass from the Upper error bar to lower error bar and should touch all error bars or vice versa)
Thank u sooo muchfor 1st 18.9/10 for the value of T and 0.1/10 for the uncertainity of T
and later 2*(deltaT/T)=x/T^2 for the uncertainity of T^2
can u upload more Q1 if u have itHere is the Q1 solved for Oct/Nov 2009 P51 . Hope u guys find this helpful !
Again if any comments or feedbacks pls do so
A hard paper indeed. Oct/Nov/2009 P51 Question 2 . I have attached the pdf file below Hope this helps u guys .AND thanks to emma for suggesting the paper
bro can you please solve o/n12 v53 q1..please....thanks in advanceHere is the Q1 solved for Oct/Nov 2009 P51 . Hope u guys find this helpful !
Again if any comments or feedbacks pls do so
Oh well , it will look shabby tbh ! (i am assuming ur talking about the triangle to draw when measuring gradient) But it doesn't matter. And if u want it to look more better then u can draw the worst fir gradient triangle Upwards , Instead of downwards like the best fit gradient ! Hope this answers ur question and helps u . Good luck for ur examsIf you draw 2 gradient lines 1 for best fir and 1 for worst fit then won’t it look shabby and how can you improve it
Waalaikumussalam Ahh well , It is like this . For eg. If Raw data is T= 2.00 +/- 0.1 Then u have to find T^2 . That will be equal to (2^2)=4 +/- (|Best T^2 value - Worst T^2 value | ) . Which is ( 4 - (1.9^2)) . Hope this answered ur question and that u understand this !Assalamualaikum brother ,for qn2. how do u find error in the given table? although its simple but i always forgotten to do this..
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