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The only point that was "out of place" was the (20, 19.8) and that too slightly. It was passing through (20,20) in my graph for the best shape.We had to join all the points.
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The only point that was "out of place" was the (20, 19.8) and that too slightly. It was passing through (20,20) in my graph for the best shape.We had to join all the points.
u in lgs?You're welcome. And no, I didnt give history. I gave it last year. Pak studies and Isl both.
It's not a difference. In my opinion it had to pass through the 20 mark.Not a big difference dude
okay, sorryNo! I'm in Beaconhouse School System
You will, if you didn't use an awkward scale and got a good enough curved shape, you'll get the two marks for the scale and curve.Well does it matter? I joined all the points! I wont get marks?
Thats great then
Thanks
no.... in a line/curve/curved line of best fit all points must not be covered......at least one point must be left out....Yeah their marks will be deducted.
Would we be given marks for listing " x and Y names " on the graph?You will, if you didn't use an awkward scale and got a good enough curved shape, you'll get the two marks for the scale and curve.
i wrote about the parallax error (line of sight) and that the rule should be as close as possible to object/lens while taking readings.I wrote avoid parallex error while taking readings and take readings more then once for accuracy
I was getting the same shape but longer (horizontally).Would we be given marks for listing " x and Y names " on the graph?
and is it imp to use 50% of the Graph paper or 1 marks will be deducted and do they allow any scaling we have done on the graph..
I got a "Swing" kind of curve... Like this (Just a rough idea)
no.... in a line/curve/curved line of best fit all points must not be covered......at least one point must be left out....
why do u think its called best fit...otherwise they would simply state draw a curve through all points
Right.how did you focused the image formed?...by adjusting the screen.....right?
and how was the image formed below the horizontal line from optical center?
should the object be placed below or aligned with the horizontal line with center?Right.
By aligning the centers.
The object should be moved up or you can state the all the three centers (object,lens,screen) must be aligned.should the object be placed below or aligned with the horizontal line with center?
thanksRight.
By aligning the centers.
The illuminated object was to be moved upwards in order to allign the centersshould the object be placed below or aligned with the horizontal line with center?
I wrote that experiment can be repeted more than once and average can be calculated, and the experiment can be repeated in dim ligththanks
and one more question....was the rule ,in lens question, fixed...i gave placing the rule as close as possible to object/lens while taking readings <suggest two practical methods of taking the readings accurately>
hey i wrote the term 'polarity' in my ans ... my frndz said it was incorrect. Can this term be used in case of voltmeters?incorrect polarities....it means that the positive terminal of the cell was not connected to the positive terminal of the voltmeter and vice versa...
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