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Physics, Chemistry and Biology: Post your doubts here!

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shk123

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shazmina said:
http://www.freeexampapers.com/#IGCSE/Physics/CIE/2000 Nov could someone help me with question no 4...btw y is de answer C...nd wats de thoery behind it...plz tnxs
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the question says its dropped frm a building n until it hits the ground..............
so its speed increases at 1st but then when it hits the ground u have to stop there as mentioned in the question!!!!!!!!!!!(mean no boucing back so no regain of speed so answer is C unlike B which shows air resistance which should nt b there)n remember it says theres no air resistance.
hope u got it!!!!!!!!!!!!:)
 
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shazmina

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shk123 said:
the question says its dropped frm a building n until it hits the ground..............
so its speed increases at 1st but then when it hits the ground u have to stop there as mentioned in the question!!!!!!!!!!!(mean no boucing back so no regain of speed so answer is C unlike B which shows air resistance which should nt b there)n remember it says theres no air resistance.
hope u got it!!!!!!!!!!!!:)
Click to expand...

tnxs a billion...i gt it...:)
 
nononona

nononona

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can you please explain:

O/N 09 no: 2 (why not B) , 8 (why not C) and 11 ( why not A)
 
Mairaxo

Mairaxo

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nononona said:
can you please explain:

O/N 09 no: 2 (why not B) , 8 (why not C) and 11 ( why not A)
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Q2- if it had constanr acceleration it would keep going up and wouldnt come down.
Q8- F=ma so a=F/m F and m are constant so a will also be constant.
Q11- mercury is denser than water so it wont move much so h will be less :)
 
gary221

gary221

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Al-Anoud said:
sooryyyy!!! hold on....http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Physics (0625)/ o/n 2009 p-12
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1) to calculate dist. in a speed/time graph..u just have to find the area under the graph.
the time taken to reach const. speed(20 m/s) is 10 sec
So, dist = 1/2 * 10 * 20 = 100m
Ans = C

2) Weight is a force, n hence is measured in newtons.
Ans = D

3)To find the time taken by the 2nd athlete, just subtract the first timing from the second.
ie 23.8 - 12.4 = 11.4 sec
Ans = B

Hope u gt it!
All credit to Nibz
 
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Al-Anoud

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gary221 said:
1) to calculate dist. in a speed/time graph..u just have to find the area under the graph.
the time taken to reach const. speed(20 m/s) is 10 sec
So, dist = 1/2 * 10 * 20 = 100m
Ans = C

2) Weight is a force, n hence is measured in newtons.
Ans = D

3)To find the time taken by the 2nd athlete, just subtract the first timing from the second.
ie 23.8 - 12.4 = 11.4 sec
Ans = B

Hope u gt it!
All credit to Nibz
Click to expand...

ty ty ty ty sooooo much! yess i got them! :) ok n thnxx to Nibz bhaii as well! :)
 
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