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if it was conc thn hydrogen would be released at the electrode instead of sodium(metal)........question had asked to liberate the metal........Why can't it be conc. NaCl solution plainly too?
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if it was conc thn hydrogen would be released at the electrode instead of sodium(metal)........question had asked to liberate the metal........Why can't it be conc. NaCl solution plainly too?
if it was conc thn hydrogen would be released at the electrode instead of sodium(metal)........question had asked to liberate the metal........
yes...concenterated and dilute are aqueous solutions.....A concentrated solution ... does it mean that it contains water?
20 volume of hydrocarbon + 150vol. o2 = 100 vol. co2 + (20 vol) h20Help me out.
eureka!
Thanks!20 volume of hydrocarbon + 150vol. o2 = 100 vol. co2 + (20 vol) h20
so 2hydc--> 10 co2
1:5...whic mean there r fice carbons in the hydrocarbon....
15*2=30..o2--->10*2(C)o2+10(h2)o
30-20=10>>(h2)o
so 2hydc-->10(h2)
so 1hydc--->5(h2)...tht equals to 10h
so hydrocarbon contains c5h10....
so the equation is 2c5h10+15O2--->10co2+10h2o
Sorry! Didn't see this until after the exam. Anyway, I guess you've to simply describe it the way you'd describe SiO2. Giant macromolecule. Tetrahedral, each Ge atom covalently bonded to 4 O (1Ge : 4O), and 1 O atom bonded to 2 Ge atoms (1O : 2Ge). Very strong covalent bonds.These two...? eureka!
Yeah, I mucked up in that one too. Dunno why that's the answer, sorry about it!0625_s13_qp_12 Question 33?
Equations in which you've gotta mention the oxidation numbers and exclude all spectator ions.What are ionic equations?
You know what? - this idiocy had come in the paper I'd seen the answer in the MS, but i dunno... Do we have to KNOW this or DERIVE it?Sorry! Didn't see this until after the exam. Anyway, I guess you've to simply describe it the way you'd describe SiO2. Giant macromolecule. Tetrahedral, each Ge atom covalently bonded to 4 O (1Ge : 4O), and 1 O atom bonded to 2 Ge atoms (1O : 2Ge). Very strong covalent bonds.
derive it......You know what? - this idiocy had come in the paper I'd seen the answer in the MS, but i dunno... Do we have to KNOW this or DERIVE it?
1. 20cm3/1000=0.02 dm3/24dm3=0.00083 moles of butynecn any1 plz ans thx View attachment 38906
3.o2 left is 150 -110= 40 cm3cn any1 plz ans thx View attachment 38906
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