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Physics, Chemistry and Biology: Post your doubts here!

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20 volume of hydrocarbon + 150vol. o2 = 100 vol. co2 + (20 vol) h20
so 2hydc--> 10 co2
1:5...whic mean there r fice carbons in the hydrocarbon....
15*2=30..o2--->10*2(C)o2+10(h2)o
30-20=10>>(h2)o
so 2hydc-->10(h2)
so 1hydc--->5(h2)...tht equals to 10h
so hydrocarbon contains c5h10....
so the equation is 2c5h10+15O2--->10co2+10h2o
 
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20 volume of hydrocarbon + 150vol. o2 = 100 vol. co2 + (20 vol) h20
so 2hydc--> 10 co2
1:5...whic mean there r fice carbons in the hydrocarbon....
15*2=30..o2--->10*2(C)o2+10(h2)o
30-20=10>>(h2)o
so 2hydc-->10(h2)
so 1hydc--->5(h2)...tht equals to 10h
so hydrocarbon contains c5h10....
so the equation is 2c5h10+15O2--->10co2+10h2o
Thanks! :)
 
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Sorry! Didn't see this until after the exam. Anyway, I guess you've to simply describe it the way you'd describe SiO2. Giant macromolecule. Tetrahedral, each Ge atom covalently bonded to 4 O (1Ge : 4O), and 1 O atom bonded to 2 Ge atoms (1O : 2Ge). Very strong covalent bonds.
You know what? - this idiocy had come in the paper :) I'd seen the answer in the MS, but i dunno... Do we have to KNOW this or DERIVE it?
 
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