because the radioactive material has finished decaying. the count rate remaining is the rate of background radiation.Physics help needed
Can anyone help me in Part b of this question please View attachment 48123
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because the radioactive material has finished decaying. the count rate remaining is the rate of background radiation.Physics help needed
Can anyone help me in Part b of this question please View attachment 48123
Part b.because the radioactive material has finished decaying. the count rate remaining is the rate of background radiation.
Half life at 33 counts so 1.6 days??Part b.
Yeah. Your answer is right but how?Half life at 33 counts so 1.6 days??
Minus background radiation (14) from initial reading(52). You will get 38. divide 38 by 2 because of half life then add background radiation again. you will get 33. Then refer to graph.Yeah. Your answer is right but how?
there's something im missing
oh..Thanks dude. You saved the dayMinus background radiation (14) from initial reading(52). You will get 38. divide 38 by 2 because of half life then add background radiation again. you will get 33. Then refer to graph.
Thank you very much. I got it now.End Q of the wood will be hottest because the heat is not conducted away from the source by the wood.
This can be demonstrated by using the apparatus shown in the diagram. If a piece of
paper is fixed tightly around the wood / copper joint, the paper will singe on the wood side (high temperature)
but not on the copper side (lower temperature).
It depends on your diode connection. If your diode is forward biased when A is positive terminal, the graph will be half wave with positive cycles between 0-1 sec and 2-3 sec. Maximum voltage on reading is 3V because it is potential divider circuit.
Hello in S07QP3 question 3(B),
why is it that the mark scheme says ignore kinetic energy and sound?
That's because the primary things the examiners are looking for in your answer is that:
a) P.E. decreases
b) decrease becomes heat
It isn't wrong to mention KE and sound, but the answer needs to focus on the energy transformations, which is mainly decrease in potential energy.
also can you help explain s10qp32 q1(b)
thanks!
have u done your part b? the answer to it should be in your part b. i am quite lost in part b but i know that u will get the answer to part c if u get part b correct.
Use the formula for kinetic energy , 1/2*m*v^2
=1/2*0.6*7^2
= 14.7 J.
Lol How does your teacher know what will come in the Board examination? And ofcourse, if it includes the portion stated in the syllabus, things from this would be bound to comeView attachment 48265 Can someone tell me when this colored thingy is one the book cover
our teacher hinted exams would include this
lol its just school exam. nothing bigLol How does your teacher know what will come in the Board examination? And ofcourse, if it includes the portion stated in the syllabus, things from this would be bound to come
Book cover of what?
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