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Is there a really difficult or tricky question that anyone has gone through please post here I wana try everything incase I've missed
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http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_s09_qp_3.pdf
Variant 2
Question 5b (ii)
Question 11 b. How do you get it?
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_s10_qp_32.pdf
Question 2c
Question 11 b.
area wont double, it will b multiplied by 4!!!
NO. he still speeds up but at a smaller rate.
Yes u r rite acceleration is the rate of change of speed so his speed may be increasing but he's acceleratingNO. he still speeds up but at a smaller rate.
(240)/(1.9 x 10^5)=1.26 x 10 ^ -3frequency = velocity/wave length..........which is equal to 240/1.95*10 to the power of 5............which is equal to 1.23* 10 to the power of negative 3 HERTZ
10(a)http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_s10_qp_32.pdf
Q NO 10 (A ) AND (B) IN THE ABOVE PASTPAPER ATTACHED LINK !!!! PLZ HELP ME ....THNX IN ADVANCE
But why when diameter halfed, area increased by 4 ???
and why you multiplied the old resistance with the area in specific ??
c u calculate d area when u do pie r square n u further multiply dis by 4 coz it was d earlier value of resistance 2 get resistance of the thinner wire of the same lengthI understand better now but I have 1 question why is pie r^2 would be 2^2 and 4? why is it 4*4?
I do understand that area decreases and resistance increases....so....plz help sorry if Im annoyinh u
No dude ur speed can be increasing but the rate at which it's increasing can slow for eg a car increases his speed from 2 to 8 m/s in only 4sec but now he increases his speed from 8 to 10 in 4 sec this means he only increased his speed by 2 in 4 sec so his acceleration decreases yet his speed does increase at slower rateIf your speeding up at a slower rate, your OVERALL speed is technically decreasing :S
no ........its slowly increasing...........eg- acceleration was 2.5 ms squared ok, so ur speed increases by 2.5 ms evry second, then acceleration decreases to, for example, 1ms squared, so ur speed increases, but only by 1 ms every second
accelerationg anode only accelerates the electrons ... it has high dc voltage connected across it ! focuscing anode makes the electrons in a beam ! usally they both r intergrated n made into onewhat is the difference between the accelerating anode and the focusing anode in the cathode ray ossiloscope????
ye
YEA...ME N U STUDY LIKE A BOSS
whatever u feel likeHow many S.f round our answers to ?
No dude better to give it to 3 or 2 decimal placeswhatever u feel like
thnx 4 d infoNo dude better to give it to 3 or 2 decimal places
but we don't know the diameter inorder to know how much it'll be after it halfed, so why you put the radias as 2 ??u need 2 noe dat resistance is directly proportional 2 length: l increases so r increases, & resistance is invrsly proportional 2 area, area decreases, resistance increases.
diameter is halved, so (hope u nderstand dis.) by pie r^2, area will b multiplied by 2^2 = 4. {the 2 is here coz u halved d diameter}
so resistance increases to 4*4, = 16 ohms.
now refer 2 d qn, they have current as 0.3A, so actually the resistance= v/i = 1.8/0.3 = 6 ohms
so 4 d ratio, u do resistance of what u need, the actual 1: resistance of r calculated hypothesis, which assumes original length.
= 6/16 =0.375
hope u understood, i noe im a horrible xplainer, n refer to ms, its v helpful.
all d best
dunno idf its diff but plz xplain 9 (c)(i) , also they've given valur in Kelvin n not C , what 2 do?Asking once again has anyone cum across a really difficult question I wana solve it incase I've missed pleaseee
in the QN its mentioned dat diameter is halved!!! so radius inverse of 1/2 is 2? u then square it 2 NOE THE RESISTANCE.but we don't know the diameter inorder to know how much it'll be after it halfed, so why you put the radias as 2 ??
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