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Physics, Chemistry and Biology: Post your doubts here!

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Manobilly

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thats_me said:
Ughhh :S i just hate estimatin :S but ya got it thx :)
n i hav another one in the same ppr 3c
Click to expand...
Hey sorry I had been working hard for that question since that time ,here is the answer,they have told us to take the reading of part (a) Which is 0.30 Amperes
and they have said that the resistor of X is twice that of the resistance in the circuit.So u know when resistance is less current is more so at 0.30 Ampres the resistance will be less ,lets say its 5.0 ohms ,so the ressitance of X is twice that so it will be 10 ohms .Its an estimate.
 
M

moon angel

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Penalopi said:
freeexampapers.com has the old papers, if you don't find it there you rnt gonna find it anywhere!
My advice: stick to recent papers!!
Click to expand...
i searched there but couldnt access it easily i guess i will not find them !! anyways , thnxx :) and good luck;)
 
M

Manobilly

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Dont believe on what you heard ,ppl didnot make the exam paper its the cie people,so chill and solve from 2002-2011.Dont believe on them ,have faith on god ,practice and thats it. Inshallah you will do good.
 
kainat husain

kainat husain

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areebaization said:
Since in part b i) It says that the pin turns 90 degree (which is 1/4 of a circle) so in part b ii) we will divide the circumference of the heated pin by 4 (to get 1/4th of the circumference, which is the expanded length) then in the next part (iii) we will add this value with the original length of the rod, making sure that the units r the same.
Here are the worked out answers:
bi) 3.8mm
bii) 3.8/4=0.95 mm
biii) 0.95mm+0.75m=
0.00095 + 0.750 = 0.75095m
Click to expand...
THANK YOU SOOOO MUCH DEAR
please can u help me in this
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_w05_qp_6.pdf
1c and d and question a :/ i dunno how 2 draw
 
M

mahmouds

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physics doubts !!!!!
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_w07_qp_6.pdf
in question 4 (b), I used a protractor and the angle must be 90 degree. is t rejected or can work.
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_s08_qp_6.pdf
question 1 (b). I need more than one possible method if you please.
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_w09_qp_6.pdf
question 4 (b) (iii), which need a drawing for measuring thickness of a converging lens.
 
thats_me

thats_me

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chaotic said:
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Chemistry (0620)/0620_w11_qp_33.pdf

Need help in:
2a (ii)
2b (iii)
7b all
Click to expand...
2b iii: Using chromatography , place a spot of the mixture on the datum line of the chromatography ppr and dip into the solvent. The diff spots that the finished chromatogram shows are the sugars in the mixture. You can find which sugars they are using the Rf values.
i knw the drawings look like ive done them with my feet :p but i hope yu get it :)
 

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thats_me

thats_me

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Manobilly said:
Hey sorry I had been working hard for that question since that time ,here is the answer,they have told us to take the reading of part (a) Which is 0.30 Amperes
and they have said that the resistor of X is twice that of the resistance in the circuit.So u know when resistance is less current is more so at 0.30 Ampres the resistance will be less ,lets say its 5.0 ohms ,so the ressitance of X is twice that so it will be 10 ohms .Its an estimate.
Click to expand...
Oh thx a lot :) but i think they say we need the reading frm the table and using a so wont it be this way 0.3*o.5 -->0.15 n thn the resistance frm the table 10.1?
 
chaotic

chaotic

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thats_me said:
2b iii: Using chromatography , place a spot of the mixture on the datum line of the chromatography ppr and dip into the solvent. The diff spots that the finished chromatogram shows are the sugars in the mixture. You can find which sugars they are using the Rf values.
i knw the drawings look like ive done them with my feet :p but i hope yu get it :)
Click to expand...

Thank you man, helped me a lot.
 
areebaization

areebaization

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kainat husain said:
THANK YOU SOOOO MUCH DEAR
Click to expand...
kainat husain said:
please can u help me in this
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_w05_qp_6.pdf
1c and d and question a :/ i dunno how 2 draw
Click to expand...


Q1 a)Complete the column headings in the table. That is we have to write units of m-mass and titha-angle. The units will be grams for mass and degree for thita.
Q1 c) Make sure that the 0-180 horizontal line of the protractor is exactly on the bench and the centre of the protractor is at the "zero end of the ruler taped to bench" Look in the figure to spot this. Drawing is optional but if u do, copy the same diagram and indicate the proper position of the centre of the protractor and the horizontal line on the protractor (0-180) should align with/should be exactly on the bench.
Q1 d) Draw (or write) that another meter rule is used to measure the distance between the bench and the elevated end of the original meter rule. MAKE SURE THAT THE RULER IS VERTICAL. Mention that the angle can then be found out by applying mathematics, you don't need to show HOW the angle can be found!
Hope it helped! :)
 
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