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OhhI didn't knew abt the formula pressure=density * height .....
Yeah actually there are two
One is Pressure=Force/Area
And the other is particularly for liquids and sometimes gases= Density*Height*10
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OhhI didn't knew abt the formula pressure=density * height .....
Ohh, but this formula is quite imp she should've given itMy teacher didn't gav me dat formula 4 pressure in gas.... I got only Boyle's law ....
It's him .... but both my tuition n class teacher didn't gav .... I think dat its not in o level's syllabusOhh, but this formula is quite imp she should've given it
Ok...But then why did you get a question related to it?It's him .... but both my tuition n class teacher didn't gav .... I think dat its not in o level's syllabus
I am my teacher's favourite lol ... so he gav me a "though" question 2 try ... dat u solved easilyOk...But then why did you get a question related to it?
That's greatI am my teacher's favourite lol ...
Happy to help... so he gav me a "though" question 2 try ... dat u solved easily
Hey! My teacher told me dat the answer is 150kPaThat's great
Happy to help
Hey! My teacher told me dat the answer is 150kPa
I already told youAnd since I did't know the exact answer I'm not sure about my answer it could be wrong too. But this was the only way to do so.
Nah ... it's OK all dat matters is dat u helped me like a true friendI already told you
AnytimeNah ... it's OK all dat matters is dat u helped me like a true friend
I would say it is Boyle's law P1V1=P2V2, ik you would be thinking, they only gave us length, but since cross-section is the same, so volume ratio should be also same a length, here is the solutionCan someone please help and explain me this physics question on pressure .....
-> A bicycle pump of length 45cm contains air with a pressure of 100kPa. In order to force air into the tyre, it is necessary to move the piston 15cm down the barrel. Calculate the pressure inside the tyre assuming the temperature is kept constant.
Thank u very very much u helped me a lotI would say it is Boyle's law P1V1=P2V2, ik you would be thinking, they only gave us length, but since cross-section is the same, so volume ratio should be also same a length, here is the solution
V1=45
v2=45-15=30
p1=100kpa
p2=?
=(45*100 000)/30=150 000=150 kpa
EZ
*just noticed my post is the 10000th*
Ur point was right but my teacher told me dat it was too direct .... the area of the cross section is considered as 'a' .... we multiply the area with the length which will give us the volume.... consider pressure to b found as 'p'I would say it is Boyle's law P1V1=P2V2, ik you would be thinking, they only gave us length, but since cross-section is the same, so volume ratio should be also same a length, here is the solution
V1=45
v2=45-15=30
p1=100kpa
p2=?
=(45*100 000)/30=150 000=150 kpa
EZ
*just noticed my post is the 10000th*
Glucose and saltsName two substances that pass out of the glomerulus into the renal capsule but are normally absent in the urine of man. what happens to these two substances in the nephron?
Could u guys answer this .
Ur point was right but my teacher told me dat it was too direct .... the area of the cross section is considered as 'a' .... we multiply the area with the length which will give us the volume.... consider pressure to b found as 'p'
45a * 100 000 = 30a *p
The 'a' is cancelled out n then we r left with :
P = 45 * 100 000 / 30 = 150 000 Pa = 15 kPa
one thing though, It should not be confused with where they are absorbed, I have seen questions, where they ask so and respond, would be the loop of Henle, which is incorrect because most glucose and salts (ions etc) are absorbed in the first loop/coil after the renal capsuleGlucose and salts
They r reabsorbed back by active transport because the body needs it
The whole of the selective reabsorption process is confusing and it remained till the day of my exam when eventually I was told to watch thisU can start watching it from 5:12, the guy pretty much explains everything
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