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Physics MCQs thread.

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Zizu1992 said:
http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_s09_qp_1.pdf
please explain question 29


v^2 = u^2 + 2ad
v = 0
u = v
s = x

F =ma & F = qE
ma = qE
ma = eE
a = eE/m

since F = e (charge) x E
v^2 = 2(eE/m) *x
x = v^2/2eE/m

x = mv^2/2eE
 
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Saturation said:
Please show the working!

I know it's negative, but how do we find the 1st column!?

V= W(work done)/charge Q (w= Fd) (F=E(eltricfield strength)Q) (F=mg)

V=EQd/Q = Ed
Also V=mgd/Q

Equate both equations

Ed=mgd/Q, the d cancels out, and you're left with E=mg/Q
They ask for Charge/Mass so
Q/m=g/E
 
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DeathDealer said:
http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_w10_qp_12.pdf

Ques 13 ?

The weight of the object will not change even if it is immersed in water. Hence D
 
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MysteRyGiRl said:
What is the component of this displacement vector in the direction XY?
A 3.0 km B 4.0 km C 5.0 km D 6.6 km
y is it c? its from oct 2010 varient 2

i think u saw wrong marking scheme ..the answer is A..5cos53 = 3.00
 
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Zizu1992 said:
http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_s09_qp_1.pdf
please explain question 29


look, work= force * distance, so distance which is x = work/force.... work in this case is kinetic energy which is 1/2mv^2
force=electric field strength*charge..... so F=Ee
therefore, x= mv^2 / 2Ee got it?
Gd luck dude :)
 
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A moving body undergoes uniform acceleration while travelling in a straight line between points
X, Y and Z. The distances XY and YZ are both 40 m. The time to travel from X to Y is 12 s and
from Y to Z is 6.0 s.
What is the acceleration of the body?
A 0.37 m s–2 B 0.49 m s–2 C 0.56 m s–2 D 1.1 m s–2
plzz dis question 2
 
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DeathDealer said:
http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_w10_qp_12.pdf

Q 22.......!


because since k is low for the first spring, the box will prevent it from breaking by over extending. Hence A
 
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@deathdealer...
the answer is A..unlike other options...in A when small mass(less heavy) is added the spring with less k will extend properly( the box will not disturb its expansion) so its sensitive to less heavy mass..but then heavy mass is added...the spring with small k will extend much..and its extension is disturbed by the cage..so is less sensative...
hope u got it
 
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@ mobeen
they are all in parallel... so the reciprocal of ((1/10 x 6) + 1/100) = 1.6 which is B
 
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