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The answer is C. we use force= stress x c.s.a (pi x radius in metres squared). the value we get is within the range of C so the answer is C.Q Nylon breaks when the stress within it reaches 1000000000 pa.
which range includes the heaviest load that couldbe lifted by a nylon thread of diameter 1mm ?
A. 2 N TO 20N
B. 20 N TO 200 N
C. 200 N TO 2000 N
D. 2000 N TO 20000 N
Guys i know the question is simple but i cant handle it !!! please solve it asap !!! thanks
Maile buzina helppok
v1=at1 becoz u=o so
fer dist h
h=at1*(t2-t1) + 1/2*a*(t2-t1)^2
h=at1t2-at1^2+1/2a(t2^2-2*t1*t2+t2^2)
h=-1/2at1^2+1/2at2^2
2h=a(t2^2-t1^2)
a=2h/(t2^2-t1^2)
option d
hope now clear if not come on
http://www.facebook.com/yubak.ghimire i will make u more clear
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