Physics MCQs thread.

[Hateexams93]

D

 

[unique840]

D

when right side will inc by distance H, the lft side will dec by H. so the difference of height will be 2H. pressure will be density*gravity*2H

 

[arlery]

Why is the answer B??

 

[Hateexams93]

it says what is increase in pressure ..so why would we add those 2 h?
EDIT : nm )) i just got it from my drawings ))

 

[unique840]

Why is the answer B??

E = F/q
E= mg/q
q/m= g/E
wight is downward, so force shud be upwards to maintain equilibrium. the direction of field is positive to negative. negative particle will have a force acting upwards. so ans is B

 

[unique840]

it says what is increase in pressure ..so why would we add those 2 h?

cox pressure difference is density*gravity*height difference
here the height difference is 2H

 

[Hateexams93]

 

[arlery]

Forget the pulley cause no friction is mentioned.

Now since torque is F x perpendicular distance.
So torque is 900 x 0.2 = 180 Nm

Then 180 = min. force x max. distance
180 = min force x 1.2
F = 150 N

So answer is B

 

[arlery]

Why is the answer B?

 

[arlery]

Why is the answer C ?

 

[Hateexams93]

hhh...can't get the answer..((

 

[Hateexams93]

Why is the answer C ?

25kv is 100% voltage , u need only 80 which is 20kV , now put these values into P=V*I and u will get the answer

 

[arlery]

hhh...can't get the answer..((

Is the answer C?

 

[arlery]

Since we know the particle was stationary before hence,
0 = m1v1 - m2v2
0 = mVx - 2mVy
2mVy = mVx
hence Vx/Vy = 2m/m
= 2/1

 

[Hateexams93]

Since we know the particle was stationary before hence,
0 = m1v1 - m2v2
0 = mVx - 2mVy
2mVy = mVx
hence Vx/Vy = 2m/m
= 2/1

oh..i thought we need to use 0.5 * m * V^2 formula ...and couldn't find the way to solve it ..thank u

 

[Hateexams93]

SOME1 answer the last Q on this page plz viewtopic.php?f=26&t=9216&start=570

 

[Hateexams93]

14
© UCLES 2008 9702/01/M/J/08
24 The Young modulus of steel is determined using a length of steel wire and is found to have the
value E.
Another experiment is carried out using a wire of the same steel, but of twice the length and half
the diameter.
What value is obtained for the Young modulus in the second experiment?
A 0.25 E B 0.5 E C E D 2E

 

[unique840]

14
© UCLES 2008 9702/01/M/J/08
24 The Young modulus of steel is determined using a length of steel wire and is found to have the
value E.
Another experiment is carried out using a wire of the same steel, but of twice the length and half
the diameter.
What value is obtained for the Young modulus in the second experiment?
A 0.25 E B 0.5 E C E D 2E

young modulus is a characteristic of material. if material is same, the young modulus is same

 

[Hateexams93]

14
© UCLES 2008 9702/01/M/J/08
24 The Young modulus of steel is determined using a length of steel wire and is found to have the
value E.
Another experiment is carried out using a wire of the same steel, but of twice the length and half
the diameter.
What value is obtained for the Young modulus in the second experiment?
A 0.25 E B 0.5 E C E D 2E

young modulus is a characteristic of material. if material is same, the young modulus is same

lol..i did all the working and got it wrong ...haha , and i knew the fact , how stupid is that..thank u for reminding ))

 

[unique840]

14
© UCLES 2008 9702/01/M/J/08
24 The Young modulus of steel is determined using a length of steel wire and is found to have the
value E.
Another experiment is carried out using a wire of the same steel, but of twice the length and half
the diameter.
What value is obtained for the Young modulus in the second experiment?
A 0.25 E B 0.5 E C E D 2E

young modulus is a characteristic of material. if material is same, the young modulus is same

lol..i did all the working and got it wrong ...haha , and i knew the fact , how stupid is that..thank u for reminding ))

ur welcum