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Physics MCQs thread.

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DeathDealer said:
Hey.......cn any1 explain dm plzzzzzz itx june 06

http://www.xtremepapers.me/CIE/Internat ... 6_qp_1.pdf

Ques 9 & 33

Some one has already answered Qno9 ...so Fro Q no 33 now..

First of all the collection is parallel so the pd across (500 ohm and 1000 ohm ) and (1000 ohm and 2000 ohm) is equal.
so for 500 ohm and 1000 ohm conncetion..
total R = 1500 ohm ...
so I = 12/1500.....= 0.008 A
so across 500 ohm resistor.
v = I R....
V = 0.008 *500....4v(point X)

Similarly,
for 2000 ohm and 1000 ohm conncetion..
total R = 3000 ohm ...
so I = 12/3000.....= 0.004 A
so across 2000 ohm resistor.
v = I R....
V = 0.004 *2000....8v (point y)

finally..Pd at X is 4V and pd at y is 8V...so the Pd between X and Y is 8-4 =4V
 
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Since body was stationary before, therefore:

0 = .5mvx^2 - .5(2m)vy^2

mvy^2 = 0.5mvx^2

so m/0.5m = vx^2/vy^2

So X/Y = 2/1
 
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XXXDARKNESSXXXX said:
this one 2!
u know the speed is ms^-1
so try option A
sqaure root of g and lambda
g=ms-2
lambda=m
so it'll be m^2 s^-2
when u take the square root of it, u'll get ms-1
which is same as the speed :)
 
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