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Physics P5 in 5 minutes !!!

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Uncertainty is calculate overall not separate lower or upper limit

Thanks for the reply :) can you also explain how to calculate the uncertainty for M/J 2011 variant 52 Q2)b ) for V/E :)
 
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Im sorry bt im also a bit confused with the absolute uncertainty thing....il let u knw as soon as i find out...
so part 2d...if u rearrange the main equation given to the form y=mx+c...the gradient will be (p/v)....in part d they have given the volume and u have already found the gradient in part c(iii)...so the value of (P) would be volume into gradient.....:)

Thank you! :)

And I can help you with the absolute uncertainties :)
I figured out how to do it, thanks to the help of many people in this thread. :D

Okay, let me show you one of the values
for the first value, it is given that l= 6 +/- o.4

so l^2 = (6)^2 = 36

The fractional uncertainty,
2 x (0.4/6) = 0.133333...

So the absolute uncertainty,
0.133333... multiplied with the l^2
so, 0.13333... x 36 = 4.8

so the final result,
36 +/- 4.8

I hope you understood :)
 
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hey i did this q, its 2012 May/ June,,,,,were u taking inverse of 54.5 x 10^-2 ???or just 54.5, cuz make sure u do, but off course u wud've done it by now :D :p
are u saying that it should be ..[0.5/54.4*10^-2]*1.83 OR [0.5/54.4]*1.83??? :)
 
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are u saying that it should be ..[0.5/54.4*10^-2]*1.83 OR [0.5/54.4]*1.83??? :)
no the error is fine (0.5/54.5) but in calulating 1/L you shud take into account the real value which is 54.5x10^2,,,,so ure error is fine and the value that u quoted 1.83 is good too
its alright :), i ws just confusing u sorry, u got it right :D
 
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Can anyone help me in how to calculate the uncertainty for O/N 2008 Q2) for D^2 :)
 
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