I'm quite confused with question 33 from summer 2012 variant 2 ( http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Physics (0625)/0625_s12_qp_12.pdf )
Can anyone explain how it's 8.0 V and not 12V?
Can anyone explain how it's 8.0 V and not 12V?
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A, because the wax melted and fell the most here.
I'm quite confused with question 33 from summer 2012 variant 2 ( http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Physics (0625)/0625_s12_qp_12.pdf )
Can anyone explain how it's 8.0 V and not 12V?
A, because the wax melted and fell the most here.
V=IR, 12= I*(10+20) , I=(12/30).
V across the 10 ohm , V= (12/30) * 10 = 4V
the total voltage is 12, so 12-4=8 which is the voltage across the 2o ohm resistor.
This is a potential divider so it divides the voltage.
I hope I helped.
I'm quite confused with question 33 from summer 2012 variant 2 ( http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Physics (0625)/0625_s12_qp_12.pdf )
Can anyone explain how it's 8.0 V and not 12V?
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