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everyone please put some notes in here, and add your questions, so that you can get help, the exam's 2 days away so be quick
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can sum1 explain me how to do question 14b from january 2012 asap
guys who has the jan 2012 qp and ms, can any1 post it here?
Uhh. I can tell you the way I did it, but it is a bit backwards.
As we know the reading on V1 is 4V, and the resistance is 10 Mega Ohms, or 1 x 10^7 Ohms.
Using V=IR you can find the current, which is 4 x 10^-7 A.
Then, using V=IR again, the second voltage being 2V, the resistance of the parallel combination is 2 /(4 x 10^-7) Which is 5 Mega Ohms.
Then, using the parallel combination of 1/R = 1/R1 + 1/R2 You will say that 1/(5 x 10^6) = 1/R1 + 1/(1 x 10^7)
Thus leading you to R1 = 1 x 10^7 Ohms, or 10 Mega Ohms.
Hope I helped in some way, I don't really know the way they expected you to work through this
I know lol, I was just too lazy to get it.It's stickied in the forums
here's this as a start
http://website.braunton.devon.sch.uk/downloads/P2 Revision notes.pdf
and this is electricity http://physics.info/charge/summary.shtml
everyone please put some notes in here, and add your questions, so that you can get help, the exam's 2 days away so be quick
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