p is equal to the gradient you calculated in part (f)
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p is equal to the gradient you calculated in part (f)
Kay...and in the next part, -p/q = y intercept? so q will come out -ve right?p is equal to the gradient you calculated in part (f)
look at the answers for nov11 ppr35 Q2 part(h) .. you can see the possible limitations and imp. thereCan't be quite sure unless I see an example question but these are usually accepted:
Errors: heat loss thru walls of container, water evaporates, and idk know to phrase this but its like human reaction error or something when you have to take a temperature reading and the corresponding time reading
Improvs: Insulation, lid, data loggers
If anyone has more please share.
Yep, lookin thru those now thnx.look at the answers for nov11 ppr35 Q2 part(h) .. you can see the possible limitations and imp. there
may be it will be negative or maybe the value of the yintercept is already negative so when u calculate it q will be positiveKay...and in the next part, -p/q = y intercept? so q will come out -ve right?
i have no idea .. they write this in all exams and i dnt undrstant it at all !!!Yep, lookin thru those now thnx.
Also in the same mark scheme, they say to draw a conclusion about proportionality of k "tested against a suitable criterion by the student." Whats this mean?
replace -e/f by the negative y-intercept .. so both the negative signs will now cancel each other outOk in the last part of Q1 where we find the gradient intercepts and constants, if the eqn is like "a = c/d - e/f" and you get a -ve intercept FROM THE GRAPH, do we replace e/f with " - intercept" to get +ve value, or just "intercept" because there already is a - in front of the e/f?
Ugh this is so confusing idk if I've explained it right...
Keep the signs for both eqn and intercept, got it tyvm 8Dreplace -e/f by the negative y-intercept .. so both the negative signs will now cancel each other out
npKeep the signs for both eqn and intercept, got it tyvm 8D
Been lookin thru forums and there's different methods...i have no idea .. they write this in all exams and i dnt undrstant it at all !!!
Ugg!!! this is really confusing :s .. but you're right logic says that the denominator should be k1 but then how do we know if it's proportional or not ?? which one is right ??Been lookin thru forums and there's different methods...
To find the % uncertainty its either "k2-k1/k2 x 100" or "k2-k1/k1 x 100" to find % uncertainty of k. My logic says to use k1 in denominator, cuz that'll give the greatest possible uncertinty...
They also say to compare that with a 20% uncertainty reference value.
Ppl say if its >20% its proportional, but others say its proportional if <2%.
Sooo...confused...
xD Ik that method, its what I've been using in lab class and mocks: if both k's are approximately equal then they are proportional. That's teacher approved actually. But then I saw these posts and the mark scheme also said "test against suitable criterion" and now idkkkkk D:Ugg!!! this is really confusing :s .. but you're right logic says that the denominator should be k1 but then how do we know if it's proportional or not ?? which one is right ??
btw mmm is asked someone who said that you could jst look at the values of k and if thy r the same then thy r proportional if thy r different thn thy r nt ... I'm nt sure of this but it's alot easier
23%Hey guys what's the weightage of this paper?
hahahahaxD Ik that method, its what I've been using in lab class and mocks: if both k's are approximately equal then they are proportional. That's teacher approved actually. But then I saw these posts and the mark scheme also said "test again suitable criterion" and now idkkkkk D:
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