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Which sensor is used to measure the length?
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Which sensor is used to measure the length?
well for pressure its piezo electric, whats for length in metres...?Measure the length of what?
If you are considering the altitude above the surface above a planet/moon/other celestial body, the .....!
Thank you so much. I roughly understand but I will fully understand if you help using an example if it is not too much work
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_4.pdf
Number 1 c(i)
I just don't get what the R should be. It is quite frustrating..
DAAAAAAAMMMN!!! THANK YOU SO SO SO SO SO SO MUCH!Not at all too much work, here it is:
First things first: all meters! Practically every formula in the syllabus would be defined for SI units alone, so they've given you values in kilometers; these need to be converted!
Anyways, it is said that the object is moved from the surface of the Earth to a point further away from it. They have asked you to calculate the change in gravitational potential of the object - this is just the difference between the gravitational potential at that point and at the surface. Since the value of G and the value of M (mass of the Earth) are constants, this only depends on R.
If we take the Earth to be a sphere with all its mass concentrated at its center, the object is 6.4 * 10^3 kilometers from the center when its at the surface. Thus, the value of R at the surface is 6.4 * 10^3 kilometers = 6.4 * 10^6 meters.
Now, once the object has been moved to an altitude (height above the Earths surface) of 1.3 * 10^4 kilometers, it is at a distance of:
13000000 + 6400000 = 19,400,000 meters from the center of the planet. Therefore, the value for R at the point where it has been taken to is 1.94 * 10^7 m.
Basically, when an object has been taken a distance away from the surface of a planet, the value of R is basically the distance from the center of the planet to the object, whether it is on the surface or above it.
Hope this helped!
Good Luck for all your exams!
well for pressure its piezo electric, whats for length in metres...?
DAAAAAAAMMMN!!! THANK YOU SO SO SO SO SO SO MUCH!
Thanks alot brother for your explanationThe question has stated that the mean kinetic energy of an ideal gas molecules at a particular temperature is given by that equation. In any sample of a gas, at any temperature, there will be a massive number of molecules/atoms interacting with each other by means of random collisions - there is no way to predict how many of these collisions occur, where they occur, etc (at least at A level!). Due to all these collisions, energy transfers also take place.
There will be some molecules going at a very low velocity, almost not moving, which will then gain kinetic energy when they collide with faster moving molecules. There will be a large percentage of molecules that have an average amount of energy and will not transfer so much energy when they collide, so their velocities remain approximately the same. Then again, there will be a small proportion of molecules that have way, way, higher kinetic energy than the others, but this number of molecules is comparatively small.
This distribution of molecular velocities is known as the Boltzmann Distribution, so the equation they've given speaks only about the average kinetic energy; it averages out all the kinetic energy values that a sample of gaseous molecules can have, so in reality, in a sample with that average velocity, there will be a small proportion of molecules that have more kinetic energy than the average and a small proportion of molecules with less kinetic energy than the calculated average.
So, the bottom line should be that, at the temperature below the value you've calculated earlier, a large proportion of molecules with the average amount of energy will not be able to move fast enough to escape from the atmosphere of Mars, but since the calculated value is only an average, there will still be a group of molecules in the same sample that have a high enough, above average, velocity to enable them to escape from the atmosphere of Mars.
Sorry for the long explanation, sorry if I bored you!
Hope this helped!
Good Luck for all your exams!
sagar65265
Oh goodness thank you SO much for all your help!
May yoube successful in your endeavors in life!!!
You really seem like a gift from God at thw moment!
THANKS AGAIN <3
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_4.pdf
Help, in question 5 part b (ii). How does area equal to 21.2 cm^2 ?
ALRIGHT!!! I GOT THIS! (but not everything though)http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_4.pdf
can some one please explain and solve Q2???!!!
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_4.pdf
can some one please explain and solve Q2???!!!
Thankyou!!!!!TIPS FOR OTHERS,
Make use of the examiner reports. They are our friends and when we have trouble, it opens the door a little for us.
Thankyou!!!!!
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