physics paper 42 expected gt and discussion

[Debonny1]

Okau please stop mentioning the content of the paper here

 

[happyperson]

Paper wasn't very easy, nuclear was really tough!

 

[Purple Chick]

My paper went all gross, i dun know how BUT I found it really tricky !

 

[happyperson]

My paper went all gross, i dun know how BUT I found it really tricky !

I think it was a hard paper.

 

[maryam fatima]

Ppr was managable except nuclear phys and photoelectric effect

where was photoelectric effect??? :O

 

[<><> Ice <><>]

My paper went all gross, i dun know how BUT I found it really tricky !

worry not
the gt is down to hell in Paper 4
just do your best on the other papers now

 

[<><> Ice <><>]

where was photoelectric effect??? :O

the photon hitting the electron thing
with momentum
ya I couldnt tell them why momentum changed
why did it?

 

[Aly Emran]

where was photoelectric effect??? :O

Photon that tackled the electron
Actually I forgot to do 1 of its part and skipped it accidentally ._.

 

[Purple Chick]

Fingers crossed !

 

[maryam fatima]

Photon that tackled the electron
Actually I forgot to do 1 of its part and skipped it accidentally ._.

ohh.... i just skipped that to do later and now i realize i forgot to do so

 

[maryam fatima]

the photon hitting the electron thing
with momentum
ya I couldnt tell them why momentum changed
why did it?

i did rest of the question but just forgot to draw the direction of electron

 

[Shadow]

Sab bta den aaplog ppr ka -_-
Guys please.. Just be patient till 8a.m.. Discuss all you like after that

 

[Shadow]

It was a tricky paper. Or maybe few of the questions were tricky. So those questions would be there to keep the threshold low That nuclear question for sure. GT would be close to below 60. I have done easier papers than this which had a GT at 56.

 

[Princess Raven]

What was the mass answer for the decay question? And what was the KE ratio answer?

 

[Distillator]

What was the mass answer for the decay question? And what was the KE ratio answer?

Mass was 130g. and KE ratio was around 0.32

 

[Aegon the Dragon]

Mass was 130g. and KE ratio was around 0.32

How did you do the K.E. ratio, by taking the max gradients of both waves and then the ratio?
I did it that way and got 3.29, since the wave with a larger max gradient was in the numerator of the question.

Don't see how it can be less than 1, unless you accidentally flipped the fraction over? Or then maybe I'm remembering it wrong.

 

[Distillator]

How did you do the K.E. ratio, by taking the max gradients of both waves and then the ratio?
I did it that way and got 3.29, since the wave with a larger max gradient was in the numerator of the question.

Don't see how it can be less than 1, unless you accidentally flipped the fraction over? Or then maybe I'm remembering it wrong.

calcualting KE was easy the formula is 1xMx(XoW)^2 . so everything gets cancelled but the amplitude. you just square the amplitudes and take the ratio and im sure it was right. Had nothing to do with gradient

 

[Aegon the Dragon]

My point is that the question asked the max. KE ratio for two waves, one of them had a higher maximum x/t gradient than the other which meant a higher max. speed and thus a higher max. KE. and that wave's KE was in the numerator. If I'm remembering it right then there is no way the answer can be less than 1.

I used 0.5xMxV^2 , and got V of both by calculating the max gradient. Not completely sure if it was right, but anyway .. no point in moping over it now. Rest of the paper went fairly well.

 

[Distillator]

My point is that the question asked the max. KE ratio for two waves, one of them had a higher maximum x/t gradient than the other which meant a higher max. speed and thus a higher max. KE. and that wave's KE was in the numerator. If I'm remembering it right then there is no way the answer can be less than 1.

I used 0.5xMxV^2 , and got V of both by calculating the max gradient. Not completely sure if it was right, but anyway .. no point in moping over it now. Rest of the paper went fairly well.

i did the same thing you did but i subsituted V=WXo. where Omega is angular frequency and Xo is peak amplitude. Found ratios using that since the aplitude was visible on the graph. And W is same for both so gets cancelled. But your answer is close to the flipped fraction. So one of us probably has it right

 

[happyperson]

What was the answer to astronaut one and the one which asked why momentum is not same?