Physics Paper 5 - Problems.

[Haris Sal11]

Got only 2 days left. Lets discuss all the problems here.

I have problems in finding percentage uncertainties in the last parts of question 2. Can anyone help me with that? Any notes? Tips? I'd be really thankful

 

[Binod Shakya]

in log or normal type

 

[talha-_-khan]

 

[Jinkglex]

i think it was u derived from best gradient - u derived from worst gradient/u derived from best gradient x 100

 

[talha-_-khan]

i think it was u derived from best gradient - u derived from worst gradient/u derived from best gradient x 100

what is the answer that you are getting according to MS it is 10% + 2 × percentage uncertainty in gradient which gives us 6.03

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_ms_52.pdf

 

[Jinkglex]

yes well 10% is from the +-3 N part but i didnt really understand why we had to do 2x gradient uncertainty either :/

 

[talha-_-khan]

yes well 10% is from the +-3 N part but i didnt really understand why we had to do 2x gradient uncertainty either :/

well i also did not understood what MS is saying but how i attempted it was like this

 

[talha-_-khan]

There were a number of possible ways of answering this part. Good candidates clearly showed
their working. The simplest method was to add the percentage uncertainty in T (10%) to twice the
percentage uncertainty in the gradient. The common error with this method was to not double the
percentage uncertainty in the gradient. Some candidate remembered to double the percentage
uncertainty in the gradient but then subtracted from it the percentage uncertainty in T. Candidates
who calculated a worst acceptable value of μ had to remember that either the maximum value of T
should to be used with the minimum value of gradient, or the minimum value of T used with the
maximum value of gradient.

 

[Binod Shakya]

Difference in worst fits slope and bet fits slope gives percentage uncertainty in slope of graph.
then to calulate percentage uncertainty
(uncertainty in slope/slope of best fit )*100%

 

[moinul]

ANYONE CAN U PLZ HELP ME WITH THIS QUESTION.
A value is given under (L/10^-2) is 54.5 +-0.5
now (1/L) needs to be calculated. For 54.5 its (1/54.5*10^-2) = 1.83
BUT FOR THIS VALUE HOW TO CALCULATE THE ABSOLUTE UNCERTAINTY(+-0.5 )

 

[Binod Shakya]

ANYONE CAN U PLZ HELP ME WITH THIS QUESTION.
A value is given under (L/10^-2) is 54.5 +-0.5
now (1/L) needs to be calculated. For 54.5 its (1/54.5*10^-2) = 1.83
BUT FOR THIS VALUE HOW TO CALCULATE THE ABSOLUTE UNCERTAINTY(+-0.5 )

i think its absolute uncertainty is also same as of value L.
I am not sure so better get confirmed first.
Plz if was mistake reply me via correct answer.

 

[Silent Hunter]

ANYONE CAN U PLZ HELP ME WITH THIS QUESTION.
A value is given under (L/10^-2) is 54.5 +-0.5
now (1/L) needs to be calculated. For 54.5 its (1/54.5*10^-2) = 1.83
BUT FOR THIS VALUE HOW TO CALCULATE THE ABSOLUTE UNCERTAINTY(+-0.5 )

wat paper is this?

 

[magnesium]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w12_qp_53.pdf
CAN SUMONE TEL THAT HOW EM SUPPOE TO DRAW ERROR BARS IN THIS Q2..??they are going out of the graph ..plz sumone help!!!!

 

[devilmask123]

ma

wat paper is this?

may june 2012 same problem here too help please

 

[Silent Hunter]

do it like -1 x (error in the original) x ( the original value of L )^-2

see if it works am not sure though

 

[moinul]

wat paper is this?

m/j year 12