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http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_52.pdf
How to do the errors part here ?> errors in log T ?
Soldier313
fb.junks
or anyone ?
for this one ...calculate the error in T values which o.2/10 = 0.02
now get the upper limit of T which is for the first one in the table lg(1.96+0.02)
subtract this from normal lg value ...which is lg1.96
so lg1.98-lg1.96 = 0.004 easy peasy
and so on