Physics paper 6 and chem paper 3 doubts

[Yousif Mukkhtar]

Guys what is all plots correct to ½ small square?

 

[IGCSE O/L student]

Your own post (lol)
IGCSE O/L student said: ↑

​

C has 1 multiplied by two atoms, which C is 2. and H is 3 multiplied by two, which means it is 6.​

ok! hahahahahahahahah...

sometimes, I am so dumb!

 

[RoyalPurple]

need help
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Chemistry (0620)/0620_w10_qp_31.pdf

last question last part..

nd how exactly do we find limiting reagent??
thnx

 

[examkiller]

oh, i didn't open your file.

its tough right ?

 

[IGCSE O/L student]

need help
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Chemistry (0620)/0620_w10_qp_31.pdf

last question last part..

nd how exactly do we find limiting reagent??
thnx

find the number of moles of both the reactants used.
ex: if the equation used is Mg+O2------>MgO
find the number of moles used using the equation: number of moles=mass/molarmass
1 mole of magnesium reacts with 1 mole of oxygen
if you find that 5 moles of oxygen and 10 moles of Magnesium is used, Oxygen is the limiting reagent, and magnesium is in excess, because 5 moles of oxygen will react with only 5 moles of magnesium. the rest of the 5 moles of magnesium is in excess.​

 

[IGCSE O/L student]

its tough right ?

to be honest, I don't get what's hard!

 

[RoyalPurple]

find the number of moles of both the reactants used.
ex: if the equation used is Mg+O2------>MgO
find the number of moles used using the equation: number of moles=mass/molarmass​

​

1 mole of magnesium reacts with 1 mole of oxygen
if you find that 5 moles of oxygen and 10 moles of Magnesium is used, Oxygen is the limiting reagent, and magnesium is in excess, because 5 moles of oxygen will react with only 5 moles of magnesium. the rest of the 5 moles of magnesium is in excess.​

thnx

 

[examkiller]

to be honest, I don't get what's hard!

the part 2/c /

 

[wooowooowoo]

what is it exactly the answer

Table 2.2
See the timing, table 2.2 has the timing till 30 seconds.
So in table 1 check the intial temp at 0 sec and then the temp at 60seconds.
Minus the figures to get the difference - 74-60 = 14

Do the same with table 2.2
81-25 = 56
Table 2.2 has a bigger temp difference therefore higher initial temp change

 

[examkiller]

Table 2.2
See the timing, table 2.2 has the timing till 60 seconds.
So in table 1 check the intial temp at 0 sec and then the temp at 60seconds.
Minus the figures to get the difference - 74-52 = 22

Do the same with table 2.2
82-25 = 57
Table 2.2 has a bigger temp difference therefore higher initial temp change

ahhhhhhhhhhhhhhh it Is simple !! gosh, btw those type of question cant be found in the book just by past papers right ?

 

[examkiller]

ahhhhhhhhhhhhhhh it Is simple !! gosh, btw those type of question cant be found in the book just by past papers right ?

thnks woo0000woooo

 

[wooowooowoo]

ahhhhhhhhhhhhhhh it Is simple !! gosh, btw those type of question cant be found in the book just by past papers right ?

To be honest, I never read any book for paper 6 physics. (It shouldn't even be considered an exam!) They give you all the formulae and they basically tell you what to do.
All you need to have is common sense and a bit of critical thinking to tackle the question properly.

 

[aliiiiiiiiii]

To be honest, I never read any book for paper 6 physics. (It shouldn't even be considered an exam!) They give you all the formulae and they basically tell you what to do.
All you need to have is common sense and a bit of critical thinking to tackle the question properly.

exactly everything is brought from the Q paper

 

[IGCSE O/L student]

the part 2/c /

the answer is Table 2.2.
in table 2.1, the initial temperature change is 74-60=14
in table 2.2, the initial temperature change is 69-25=44
so, it is table 2.2, you should show the two calculations to prove your answer

 

[Nasirkhan09]

isn't it supposed to be like this?:
C has 1 multiplied by two atoms, which C is 2. and H is 3 multiplied by two, which means it is 6.

thats the right answer...

 

[wooowooowoo]

the answer is Table 2.2.
in table 2.1, the initial temperature change is 74-60=14
in table 2.2, the initial temperature change is 69-25=44
so, it is table 2.2, you should show the two calculations to prove your answer

Oops! Yeah, that's the way you do it examkiller

I updated my post (should've checked the ms before commenting here)

Table 2.2
See the timing, table 2.2 has the timing till 30 seconds.
So in table 1 check the intial temp at 0 sec and then the temp at 30seconds.
Minus the figures to get the difference - 74-60 = 14

Do the same with table 2.2
81-25 = 56
Table 2.2 has a bigger temp difference therefore higher initial temp change

 

[IGCSE O/L student]

thats the right answer...

thanks

 

[RoyalPurple]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Chemistry (0620)/0620_s09_qp_3.pdf

Q5 b .. how to do it??

 

[Manobilly]

Dude, sorry to barge in but that's wrong. The correct answer is this ↓. People might get confused

I didnt write the answers ,but I just explained how are we going to multiply!

 

[Moi]

PHYSICS:

1) Please Anyone explain to me what's a Parallax action and HOW to explain it (if incase i wanted to write it in the lense question)
2) You know how in Summer 2005 and winter 2008 there is this table with Quantity Measured and you need to underline one of the recorded values !! How do we do that ?? Is there a way to solve rather than guessing ??
EXAMPLE:

Quantity Measured Recorded Values
-----------------------------------------------------------------------
The Weight of an 0.7 N
empty 2250 cm^3 7.0 N
glass Beaker 70 N
-----------------------------------------------------------------------
The volume of 0.6 cm^3
one sheet of this 6.0 cm^3
examination paper 60 cm^3

And so on .....