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Physics: Post your doubts here!

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Muhammad Ahmer Ali

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Can anyone plz tell me that why daughter particles go in opposite directions when a parent nucleus is split relating this to the concept of momentum......
 
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sadman sakif

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GUYS PLEASE you gotta help me out!!!!!! our exam has been postponed !!!!!! please do posts what came tomorrow !!!! please it would be really helpful
 
Goku

Goku

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How do you solve questions that involve % uncertainties :'(

pleeeeeeease?
 
sahania

sahania

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Muhammad Zammad said:
Can anyone please tell me how a Hall Probe look like? upload a sketch or something. Relative to physics p5.
Click to expand...
http://www.xtremepapers.com/community/attachments/hallp-gif.1465/
http://www.phys.ufl.edu/demo/5_ElectricityMagnetism/M_SemiconductorsandTubes/HallProbe.html
Hall Probe is a device to measure magnetic field strength.
It has a power source and a voltmeter connected to it. Power source is required to make current flow through the device. The slice of the semiconductor has to be perpendicular to the magnetic field lines so that the current is flowing in the direction perpendicular to the lines and thus we get maximum deflection of charged particles.
Similarly, a voltmeter is connected to measure the potential difference across two faces of the semi-conductor (Hall voltage).
The syllabus asks us to know how to use a "calibrated" hall probe.
We can calibrate a hall probe using helmholtz coils. The hall probe can be placed perpendicular to the field lines between the two coils and preferably at the mid-point of the distance between the coils. We can use a formula to calculate the B at the mid-point. So, the corresponding voltage of the hall probe in fact is equal to that value of B. We can vary the value of B by varying the current through the coils and thus we get different values of V for corresponding value of B. The, draw a calibration curve of V against B. And when placed in a field of unknown field strength, check the V and find the required value on X-axis for the value of V on y-axis, which would be the value of B.
 
sahania

sahania

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Diamona151294 said:
need help.....
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_2.pdf
^q5a and q6c and exp q8bii and iii
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_22.pdf
q4 part b and c. answer is 6.4 for c.
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_21.pdf
q4bii. ans is 4e. pls explain
please reply asap!
Click to expand...

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_2.pdf
Q5a
phase difference = 180 degrees
path difference = (n+1/2) pie

Q6c
because the path being considered is horizontal and gravitational force is applied vertically
 
sahania

sahania

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M would be zero when there's a destructive interference so the phase difference of the 2 waves at P = 180
and the formula of path difference would be of destructive interference
 
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