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Physics: Post your doubts here!

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Any one can help me with M/J 2011 paper 51 question 2 (d) and so on. How can you get the uncertainty of N if gradient=(NkT/A) Pleaase help, just the uncertainty
 
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Q13
torque with 0.1m=3Nm,so by cross multiplying find torque with 0.15m,that is=4.5Nm.
then find force for both the torques by F=torque/diameters in metres....
add both the forces ,that's equal to tension.

Q15
mass is inversely propotional to velocities,
so if velocity of 2kg trollry =2m/s then velocity of 1 kg=4m/s
find out the kinetic energy of both trolleys by using 0.5mv2
and add both kinetic energies.

Q22
find cross sectional area of wire using 2pi(0.00025)
the assume original length as any number like 2m
then by using stress=force/area find stress
and then apply formula of youg modulus =stress x original length/extension to find extension...
then( extension/original length+ extension)x 100

hope it helped.

it really did! thanks alottt
 
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Q23
first find frequency of wave using f=speed/wavelength that is = 6.25Hz
then find speed of particle P=2 x 2(amplitude)x pi x 6.25
then use formula of kinetic energy to find max K.E that will be 0.00404J=4.04mJ

Q6
obviously if we apply force perpendicular to the direction of motion,the direction would change bt since no force is applied parallel to motion,the there will be no change in speed.....

Q11
first find out force produced by mass,F=2 x 9.81=19.62N

find out the resultant force acting on the block by F =19.62-6=13.62N

hence acceleration of block=resultant force/total mass=13.62/10=1.362=1.4m/s2


Q3
just find change in temperature using Final -initial=14-(-6.5)=20.5C
 
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Q23
first find frequency of wave using f=speed/wavelength that is = 6.25Hz
then find speed of particle P=2 x 2(amplitude)x pi x 6.25
then use formula of kinetic energy to find max K.E that will be 0.00404J=4.04mJ

Q6
obviously if we apply force perpendicular to the direction of motion,the direction would change bt since no force is applied parallel to motion,the there will be no change in speed.....

Q11
first find out force produced by mass,F=2 x 9.81=19.62N

find out the resultant force acting on the block by F =19.62-6=13.62N

hence acceleration of block=resultant force/total mass=13.62/10=1.362=1.4m/s2


Q3
just find change in temperature using Final -initial=14-(-6.5)=20.5C

Thank you for the great help.
 
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When drawing error bars how long do the error bars have to be? Do each of the length of the error bars depend on their uncertainty or are all the same length?
Also, how do you draw the worst line of best fit??

Please help, this is emergency!
 
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When drawing error bars how long do the error bars have to be? Do each of the length of the error bars depend on their uncertainty or are all the same length?
Also, how do you draw the worst line of best fit??

Please help, this is emergency!

it depends on uncertainity just divide the error by value of 1 division and you get no of boxes and steepest line from left to right of error bar of first and last bar making sure it passes through all bars
 
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error bars will be horizontal n u draw two worst acceptable lines frm right to left and left to right n chose d one dat is most deviated frm d best fit line.
u got it?:cautious: :p
reply denekeliye thanx yaar!!! per do do worst acceptable lines :O :O ???jaan nikal jayegi meri...ab toh vaaat lagney wali hain! :'( :'(
 
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11. Pressure increases with depth (p=density x g x height). So does Force, because F=pA and A is constant.
18. Pressure=density x g x height. The height is the difference in height between the two tubes. The difference in height is 2h, because the liquid in the right hand tube moves h metres up and the liquid in the left hand tube moves h metres down.

14. At the highest point, its vertical velocity = o ms-1, so its K.E. can only come from its horizontal component, which is constant throughout, and is equal to xcos45.
19. p=F/A and density=mass/volume. F/g=mass and A x height=volume.
23. This is something you've just got to memorise.
25. D is correct because points equidistant from a node = to a node, and all nodes have the same displacement and all points on a wave have the same frequency. A is wrong because not all points on a stationary wave are in phase; only points in a certain segment. B is wrong because not all points have the same displacements, e.g. nodes have 0 and antinodes have maximum. C is wrong because only points in a segment are in phase.
27. An electric field is defined as the force per unit positive charge placed inside the field. That's F/q.
 
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