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Physics: Post your doubts here!

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Sure :
5a)
its easier if u convert the angle in radian ie multiply by (π/180°) ----> 60° = π/3 rads.
n c this --->
thts whr the new wave will start!

So it would look like :
24790-ac9bc08b6941c67bdaeafed08411d402.jpg


Correct me if it is wrong. ZaqZainab Suchal Riaz
Suchal Riaz is this correct :) ?
 
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upload_2014-4-20_0-30-59.png

MS :
force on mass = mg (where g is the acceleration of free fall
/gravitational field strength)
g = GM/r^2
if r @ h, g is constant
ΔEP = force × distance moved
= mgh
 
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16:
B is incorrect because the velocity does not decrease uniformly (it's roughly parabolic), which means height of the ball does not increase uniformly, which means the potential energy of the ball does not increase uniformly (since Ep = mgh and rate of h is not constant).
26:
HOPE IT HELPS

Emm i dont find any explanation for 26 but thanks for helping with 16
 
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Emm i dont find any explanation for 26 but thanks for helping with 16
-->Intensity is directly propotional to square of a
it means if A in two times, I is four times
-->Intensity is inversely proportional to area
by first rule and second rule, E increase 4 times due to doubling of A but decreases 1/2 times due to halving of area. so E(new) = E*4/2=2E
 
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okay so the range is from 1.5 to 3.5 V for 0-25 C
Volt meter reads only upto one decimal place, 0.1 V. 0.1V/1V * 25 C = 2.5 C. it means that the temperature can be known close to 2.5 C of the real values.
and secondly the circuit has another problem. the line is not straight. so same change for temperature is not same change for voltage for all values. it changes.
 
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1,983
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3,044
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Sure :
5a)
its easier if u convert the angle in radian ie multiply by (π/180°) ----> 60° = π/3 rads.
n c this --->
thts whr the new wave will start!

So it would look like :
24790-ac9bc08b6941c67bdaeafed08411d402.jpg


Correct me if it is wrong. ZaqZainab Suchal Riaz
its correct.
the new wave will have phase difference of 60 degree. which means that 1/6 of the one wavelength. which means one big block of 10 small blocks.
and the new amplitude will be √(2) of A.
which is almost 0.7a
 
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okay so the range is from 1.5 to 3.5 V for 0-25 C
Volt meter reads only upto one decimal place, 0.1 V. 0.1V/1V * 25 C = 2.5 C. it means that the temperature can be known close to 2.5 C of the real values.
and secondly the circuit has another problem. the line is not straight. so same change for temperature is not same change for voltage for all values. it changes.
I didn't get this thing, did u mean 1.5 to 3.5 ohms if not how did you get volts?
 
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